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3 years ago

Solve each system of equations

Mathematics

1 answer:

barxatty [35]3 years ago

6 0

Answer:

(0,5)

Step-by-step explanation:

-2x+6y=30

5x+2y=10

I'm going to use elimination.

I'm choosing this method because both equations are in the same form.

They are in the form ax+by=c.

So in order to use elimination, I need one of my columns that contain the variables to contain opposites. Neither one of my columns with the variables have that. Example -2x and 5x are not opposites and 6y and 2y are not opposite.

I'm going to multiply both sides of equation 2 by -3. This will help me to achieve the opposites in a column.

So the system becomes:

-2x+6y=30

-15x-6y=-30

---------------------If we add the columns you will see that the variable y get's eliminated. Let's do that.

-2x+6y=30

-15x-6y=-30

-------------------Adding!

-17x+0y=0

-17x =0

x =0

So using one of the equations (you choose; doesn't matter which one you pick) along with x=0, I'm going to find y.

I choose equation 2.

That is I choose 5x+2y=10 along with x=0 to find y.

5x +2y=10 with x=0

5(0)+2y=10

0 +2y =10

2y=10

y=10/2

y=5

The solution is (x,y)=(0,5).

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3 years ago

A train heads south out of Bloomington an hour after a northbound train

ahrayia [7]

9514 1404 393

Answer:

northbound: 2.5 hours
southbound: 1.5 hours

Step-by-step explanation:

When the second train leaves the station, the trains are already 63 miles apart. The rate of increase of their separation is (57 +63) = 120 miles per hour. The remaining 243-63 = 180 miles of separation will be achieved in ...

(180 mi)/(120 mi/h) = 1.5 h

The northbound train will have traveled 2.5 hours; the southbound train will have traveled 1.5 hours when the trains are 243 miles apart.

7 0

3 years ago

Which equation has a graph that is perpendicular to the graph of -x + 6y = -12?

serious [3.7K]

Answer:

c) 6x + y = -52 is required equation perpendicular to the given equation.

Step-by-step explanation:

If the equation is of the form : y = mx + C.

Here m = slope of the equation.

Two equations are said to be perpendicular if the product of their respective slopes is -1.

Here, equation 1 : -x + 6y = -12

or, 6y = -12 + x

or, y = (x/6) - 2

⇒Slope of line 1 = (1/6)

Now, for equation 2 to be perpendicular:

Check for each equation:

a. x + 6y = -67 ⇒ 6y = -67 - x

or, y = (-x/6) - (67/6) ⇒Slope of line 2 = (-1/6)

but $\frac{1}{6} \times \frac{-1}{6} \neq -1$

b. x - 6y = -52 ⇒ -6y = -52 - x

or, y = (x/6) + (52/6) ⇒Slope of line 2 = (1/6)

but $\frac{1}{6} \times \frac{1}{6} \neq -1$

c. 6x + y = -52

or, y =y = -52 - 6x ⇒Slope of line 2 = (-6)

$\frac{1}{6} \times (-6) = -1$

Hence, 6x + y = -52 is required equation 2.

d. 6x - y = 52 ⇒ -y = 52 - 6x

or, y = 6x - 52 ⇒Slope of line 2 = (6)

but $\frac{1}{6} \times 6 \neq -1$

Hence, 6x + y = -52 is the only required equation .

3 0

3 years ago

Read 2 more answers

What is the side length, s, of the square? A= 81 m2

Alborosie

Answer:

The side length is 9 m

Step-by-step explanation:

The area of a square is given by

A = s^2

81 = s^2

Take the square root of each side

sqrt(81) = sqrt(s^2)

9 =s

The side length is 9 m

4 0

3 years ago