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Trava [24]
3 years ago
5

Explain how you can tell if 4 is a factor of 30

Mathematics
1 answer:
givi [52]3 years ago
8 0
4 is not a factor of 30 because the factor of 30 is:
2*15
6*5
3*10
1*30
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Simplify 2x-3(y-2x) 8x-3y
olchik [2.2K]

Answer:

16x - 6y

Step-by-step explanation:

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What is the solution to the compound inequality -8<2x-4<2
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I need help with this question.
docker41 [41]

Answer:

D. x=8.57

Step-by-step explanation:

We can see from our graph that triangle CED is similar to triangle CBA. Side length BA corresponds to ED and Side length AC corresponds to DC.

Since we know that corresponding sides of two similar triangle are in the same proportion. To find value of x we will set proportion of the corresponding sides of our given triangles equal.

\frac{x+15}{15} =\frac{11}{7}          

Upon cross multiplying our given equation we will get,

7(x+15)=11\times 15

Upon distributing 7 we will get,

7x+105=11\times 15

7x+105=165

7x=165-105

7x=60  

x=\frac{60}{7}

x=8.5714285714285714\approx 8.57

Therefore, x equals 8.57 and option D is the correct choice.


3 0
4 years ago
Help plzzz I'm almost done ​
iren2701 [21]

Step-by-step explanation:

7 and 4 are solutions the others not

8 0
3 years ago
Two fair dice are rolled. Determine whether the events are dependent or independent. (a) (the first die shows 3) and (the two di
Alborosie

Answer: The events are independent

a) p = 1/36 b) p = 5/216

Step-by-step explanation: both events are independent because the fact that the first die shows it sample space {1, 2, 3, 4, 5, 6} does not stop the second die from showing it own sample space too which is {1, 2, 3, 4, 5, 6}.

The sample space of first die = {1, 2, 3, 4, 5, 6}

The sample space of second die = {1, 2, 3, 4, 5, 6}

The sample space of 2 dice rolled at once is seen as attachment to this answer, find attachment below.

Probability that an event will occur = number of time the event will occur / total number of possible outcome of the event

a)

Probability that first die will show 3 = number of times 3 shows up in the event / total number of outcome of the die = P (3)

P (3) = 1/6

Probability that 2 dice sum up to give 7 = 6/ 36 = 1/6 ( from the sample space for 2 dice attached, it is seen that the sum of 7 comes out 6 times and the total sample space is 36)

P (first die show 3) = 1/6

P ( 2 dice sum to 7) = 1/6

P ( first die show 3) and P ( 2 dice sum to 7) = 1/6 * 1/6 = 1/36.

b)

Probability of the first die showing 4 = P(4) = 1/6

Probability of 2 die sum up to give 8 = 5/36

P ( first die show 8) and P ( 2 die sum up to give 8) = 1/6 * 5/36 = 5/216

7 0
3 years ago
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