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WINSTONCH [101]
3 years ago
6

Find the distance between the pair of parallel lines, y = -2x+1 & y = -2x+16.

Mathematics
1 answer:
balu736 [363]3 years ago
4 0
Given \ the \ equations \ of \ two \ non-vertical \ parallel \ lines:\\\\y = mx+b_1\\y = mx+b_2\\\\the \ distance \ between \ them \ can \ be \ expressed \ as : \\\\d= \frac{|b_{1}-b_{2}|}{ \sqrt{ m^2+1} }

y = -2x+1\\y = -2x+16 \\\\\\d= \frac{|b_{1}-b_{2}|}{ \sqrt{ m^2+1} } =\frac{| 1-16|}{ \sqrt{ (-2)^2+1} } =\frac{| -15|}{ \sqrt{ 4+1} } =\frac{15}{\sqrt{5}}\cdot \frac{\sqrt{5}}{\sqrt{5}}=\\ \\\\=\frac{15\sqrt{5}}{5}=3\sqrt{5}\approx 3\cdot 2.24 \approx 6.72


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andrew11 [14]

Answer:

F' = (7, 6)

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I' = (-2, -5)

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Step-by-step explanation:

The rule of reflection over the y-axis is, (x, y) ---> (-x, y). So change all the x values into the opposite signs. So the -7 of F would turn into just 7, the 1 of R would turn into -1, the 2 of I would turn into -2, and -6 of O would turn into just 6.

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4 years ago
What is 7/8ths of 40
devlian [24]
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3 years ago
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pashok25 [27]
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3 years ago
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mojhsa [17]

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Sergeeva-Olga [200]
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3 years ago
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