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Arisa [49]
3 years ago
14

Consider the exponential function f(x) = 3(1/3)^x and its graph

Mathematics
2 answers:
sweet [91]3 years ago
7 0

An exponential function is of the form f(x)=ab^{x}

where a ≠0, b > 0 , b ≠1, and x is any real number.

when b > 1, the graph increases.

when 0 < b < 1, the graph decreases.

a = initial value,r = growth or decay rate

x = number of time.

The given Exponential function is

f(x)=3(\frac{1}{3})^x

Among the options given the ones which are true for the given function are:

The growth value of the function is 1/3

The function shows exponential decay

The function is a stretch of the function f(x)  =(\frac{1}{3})^x


Alona [7]3 years ago
3 0
<span>I think these ones should be correct,
The growth value of the function is 1/3
</span><span>The function shows exponential decay
</span><span>The function is a stretch of the function f(x) = (1/3)^x</span>
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7 1/6 = 5 2/5 + p<br><br> p = ???
Crank

\huge\textbf{Hey there!}

\mathbf{7\dfrac{1}{6} = 5\dfrac{2}{5} + p}

\rightarrow\mathbf{7 \dfrac{1}{6} = 5\dfrac{2}{5} + p}

\mathbf{\rightarrow p + 5\dfrac{2}{5}= 7\dfrac{1}{6}}

\mathbf{\rightarrow {p + \dfrac{27}{5}=\dfrac{43}{6}}}

\text{SUBTRACT }\rm{\dfrac{27}{5}}\text{ to BOTH SIDES}

\mathbf{p + \dfrac{27}{5} - \dfrac{27}{5} = \dfrac{43}{6}- \dfrac{27}{5}}

\text{CANCEL out: }\rm{\dfrac{27}{5} - \dfrac{27}{5}}\text{ because it gives you 0}

\text{KEEP: }\rm{\dfrac{43}{6} - \dfrac{27}{5}}\text{ because it help solve for the p-value}

\text{NEW EQUATION: }\rm{p = \dfrac{43}{6} - \dfrac{27}{5}}

\large\textsf{SIMPLIFY IT!}

\mathbf{p = \dfrac{53}{30} \approx p = 1\dfrac{23}{30}}

\huge\boxed{\textsf{Therefore, your answer is: \boxed{\mathsf{p = 1\dfrac{23}{30}}}}}\huge\checkmark

\huge\textbf{Good luck on your assignment \&}\\\huge\textbf{enjoy your day!}

~\frak{Amphitrite1040:)}

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2 years ago
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