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prisoha [69]
2 years ago
13

Find the L.C.M of x^2+x , x^2-1 , x^2-x

Mathematics
2 answers:
Shalnov [3]2 years ago
8 0

Answer:

x\cdot(x+1)\cdot(x-1)=x^3-x

Step-by-step explanation:

To find the LCM of any integer, we take the product of all the <em>highest powers</em> of the factors that appear in the numbers. Factoring our three given expressions gives us the products

x^2+x=x\cdot(x+1)\\x^2-1=(x+1)\cdot(x-1)\\x^2-x=x\cdot(x-1)\\

Our LCM will be a product of some powers of x, x+1, and x-1. The most each factor occurs in the three expressions is once, so our least common multiple is

x^1\cdot(x+1)^1\cdot(x-1)^1

which can be simplified to x^3-x

grin007 [14]2 years ago
8 0

Answer:

Step-by-step explanation:

x² + x = x * (x + 1)

x² - 1  = (x - 1)(x + 1)                      {a² - b² = (a+b)(a-b)}

x² - x = x * (x - 1)

LCM = x * (x + 1) * (x - 1)

     

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