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Zigmanuir [339]
4 years ago
11

2 Points Multiply (x - 3)(4x + 2)4 What is it please help

Mathematics
1 answer:
Anton [14]4 years ago
7 0

Answer:

Not 100% sure but i think its 16x -24

Step-by-step explanation:

(x - 3)(4x + 2)4

multiply the 4 by 2 and 4x to get

(x - 3)(16x + 8) then multiply like terms

x * 16x = 16x

8 * -3 = -24

16x - 24

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The volume of the cone is 25.12 the height is 6 what is the area of the base​
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153.94

Step-by-step explanation:

AB=πr2=π·72≈153.93804

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A basketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. She misses the first shot 40% o
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A vase is in the shape of a rectangular prism. It has a base area of 40
Reptile [31]

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40/10

Step-by-step explanation:

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2 years ago
Plz help, I'm taking an Advanced class (Algebra) Will give brainliest ✔✔✔✔✔✔✔✔✔
bija089 [108]

Part A:

The average rate of change refers to a function's slope. Thus, we are going to need to use the slope formula, which is:

m = \dfrac{y_2 - y_1}{x_2 - x_1}

  • (x_1, y_1) and (x_2, y_2) are points on the function

You can see that we are given the x-values for our interval, but we are not given the y-values, which means that we will need to find them ourselves. Remember that the y-values of functions refers to the outputs of the function, so to find the y-values simply use your given x-value in the function and observe the result:

h(0) = 3(5)^0 = 3 \cdot 1 = 3

h(1) = 3(5)^1 = 3 \cdot 5 = 15

h(2) = 3(5)^2 = 3 \cdot 25 = 75

h(3) = 3(5)^3 = 3 \cdot 125 = 375


Now, let's find the slopes for each of the sections of the function:

<u>Section A</u>

m = \dfrac{15 - 3}{1 - 0} = \boxed{12}

<u>Section B</u>

m = \dfrac{375 - 75}{3 - 2} = \boxed{300}


Part B:

In this case, we can find how many times greater the rate of change in Section B is by dividing the slopes together.

\dfrac{m_B}{m_A} = \dfrac{300}{12} = 25


It is 25 times greater. This is because 3(5)^x is an exponential growth function, which grows faster and faster as the x-values get higher and higher. This is unlike a linear function which grows or declines at a constant rate.

7 0
4 years ago
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