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Gre4nikov [31]
3 years ago
9

Insert parentheses to make each statement true -8+3-2+7=-16

Mathematics
1 answer:
quester [9]3 years ago
8 0
 this is the answer and where the parentheses -8+(3-2)+7=-16
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An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p
horrorfan [7]

Answer:

a = -0.3575

Step-by-step explanation:

The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.

The points A and B are located where

y=a(x+1)(x-5)=0

This gives

x=-1

y=5

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

B_x=A_x+\frac{2}{tan(60)} =-1+\frac{2\sqrt{3} }{3}

Thus the coordinates of B are:

B=(-1+\frac{2\sqrt{3} }{3},2)

Now this point B lies on the parabola, and therefore it must satisfy the equation  y=a(x+1)(x-5).

Thus

2=a((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)

Therefore

a=\frac{2}{((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)}

\boxed{a=-0.3575}

8 0
3 years ago
How is the difference 14/15-5/12 written as a decimal?
belka [17]
14/15-5/12 = 31/60

31/60 = 0.5166...
8 0
3 years ago
Read 2 more answers
What is the x-coordinate of the soultion y=x+2 y=-x+6
Kay [80]
<span>x+2 = -x+6
</span>2x+2 = 6
2x = 4
x = 2
6 0
3 years ago
Read 2 more answers
Please help with step by step. Thank you
o-na [289]

Answer:

  • SU = 2
  • PX = 6 2/3

Step-by-step explanation:

The product of distances to the circle along a secant is the same for all secants intersecting a given point.

a. Secants SW and QT intersect at U. Thus ...

  (UT)(UQ) = (US)(UW)

  (1.5)(4) = (SU)(3)

  SU = (4)(1.5)/3

  SU = 2

__

b. Secants PT and PX intersect at P. Thus ...

  (PQ)(PT) = (PR)(PX)

  PX = (PQ)(PT)/PR) = (2.5)(2.5 +4 +1.5)/3 = 20/3

  PX = 6 2/3

4 0
3 years ago
If 1 is the zero of polynomial p(x) x2a- 3xa+3x2-1 find the value of a
bonufazy [111]

The value of a can be obtained by substituting 1 to the equation and equating p(1) = 0.

<span> p(x) = x2a - 3xa + 3x2 -1 </span>

<span>p(1) = a - 3a +3 -1 = 0</span>

<span>therefore a =1</span>

the equation now becomes p(x) = x2 - 3x + 3x2 -1

3 0
4 years ago
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