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lord [1]
3 years ago
14

I would really appreciate if someone would help me i don’t understand

Mathematics
1 answer:
alekssr [168]3 years ago
6 0

Answer:

D. 48

Step-by-step explanation:

In the experiment, 16/40 landed exactly on heads. If you do 16/40 * 3/3 = 48/120.

This means that you can estimate 48 of the next 120 trials have 2 coins showing heads.

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Solve for a side in right triangles (soh cah toa)
nevsk [136]
Cos(35) = x/6
or 6 * cos(35) = x
3 0
3 years ago
For the region bounded by y=2x​, the​ x-axis, and x=1​, determine which of the following is​ greater: the volume of the solid ge
telo118 [61]

Answer:

The correct answer B) The volumes are equal.

Step-by-step explanation:

The area of a disk of revolution at any x about the x- axis is πy² where y=2x. If we integrate this area on the given range of values of x from x=0 to x=1 , we will get the volume of revolution about the x-axis, which here equals,

\int\limits^1_0 {(pi)y^{2} } \, dx

which when evaluated gives 4pi/3.

Now we have to calculate the volume of revolution about the y-axis. For that we have to first see by drawing the diagram that the area of the CD like disk centered about the y-axis for any y, as we rotate the triangular area given in the question would be pi - pi*x². if we integrate this area over the range of value of y that is from y=0 to y=2 , we will obtain the volume of revolution about the y-axis, which is given by,

\int\limits^2_0 {pi - pix^{2} } \, dy = \int\limits^2_0 {1 - y^{2}/4 } \, dy

If we just evaluate the integral as usual we will get 4pi/3 again(In the second step i have just replaced x with y/2 as given by the equation of the line), which is the same answer we got for the volume of revolution about the x-axis. Which means that the answer B) is correct.

7 0
3 years ago
Please, Help with this MATH question.
hammer [34]
Y in the second equation
6 0
2 years ago
Read 2 more answers
Please help me please I reallly need help
kiruha [24]

Answer:

we have:

v  =  \frac{1}{3} \pi \: r {}^{2}h \\  \\  =  > 60\pi =  \frac{1}{3} \pi \: r {}^{2} h \\  \\  <  =  > 180 = r {}^{2} h

=> r²h = 10.18 = 9.20 = 5.36 = 6.30 = 4.45 = 12.15

=> only r²h = 5.36 satisfy the problem

=> h = 5

h = 5 r = 6

h = 5 r = 6=> d = 12

3 0
3 years ago
How do i find the area between the two curves
viktelen [127]
A=22/10

A=integral(a,b) [f(x)-g(x)]dx

Since the function is even (the function is mirrored over the y axis) we can evaluate the integral from 0 to 1 and then multiply our answer by 2 since we have the same area on each side of the y axis.

We get A=2*int.(0, 1)[(x^2)-(-2x^4)]dx

Now we can integrate by term.

2*[int.(0, 1)[x^2]dx+int(0, 1)[2x^4]dx]

Now factor out constants.

2*[int(0,1)[x^2]dx+2int(0,1)[x^4]dx]

Now integrate.

2*[(x^3/3)|(0,1) + 2*(x^5/5)|(0,1)]

Now solve.

2*[(1/3)+2*(1/5)]

=22/10

Hope you can decipher what I wrote!
4 0
3 years ago
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