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Jlenok [28]
3 years ago
10

Write a loop to print 56 to 70 inclusive (this means it should include both the 56 and 70). The output should all be written out

on the same line.
Computers and Technology
1 answer:
IRINA_888 [86]3 years ago
4 0

Answer:

for i in range(56,71):

   print(i)

Explanation:

By the range 56 to 71 it means that for loop will run when i=56 to i=71, but the upper bound is one less than the upper bound, and which is 70. So the above loop will print integers from 56 to 70.

And the above code is in Python.

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Please explain what steps you will take to prevent hackers from getting access to your personal information.
yuradex [85]
The steps I would take are 1. Making a strong password with symbols and numbers. 2. I will set up a 2 way authentication ther for if someone would be trying to hack me I would get an alert in order to stop the attempt. 3 I will not use the same password each time.
4 0
3 years ago
Before guis became popular, the _______________ interface was the most commonly used.
sineoko [7]
<span>Before GUIs became popular, the command line interface (CLI) was the most commonly used.
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6 0
3 years ago
Create a class Str that subclasses str. Add a method to the subclass that checks if the string does not start with a given strin
Stolb23 [73]

Answer:

#include <iostream>

using namespace std;

class Str{  ///baseclass

   public :

   string super_str;

   string getStr()

   {

       return super_str;

   }

   void setStr(string String)

   {

       super_str=String;

   }

};

class str : public Str{   //inheriting Str publicly

   public :

       string sub_str;

       string getstr()

       {

           return sub_str;

       }

       void setstr(string String)

       {

           sub_str=String;

       }

       bool notstartswith()

       {

           int n=sub_str.length();   //to find length of substr

           bool flag=false;

           for(int i=0;i<n;i++)     //Loop to check beginning of Str

           {

               if(super_str[i]!=sub_str[i])

               {

                   flag=true;

                   break;

               }

           }

           return flag;

       }

};

int main()

{

   str s;    //object of subclass

   s.setStr("Helloworld");  

   s.setstr("Hey");

   if(s.notstartswith()==1)     //checking if str is substring of Str

       cout<<"Str does not start with str";

   else

       cout<<"Str starts with str";

   return 0;

}

OUTPUT :

Str does not start with str

Explanation:

Above program is implemented the way as mentioned. for loop is being used to check the beginning of the str starts with substring or not.

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4 years ago
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topjm [15]

Answer:

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Clear formatting-B

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Explanation:

7 0
3 years ago
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