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Dovator [93]
3 years ago
14

Technical colleges offer certification in audio engineering through programs that are normally from 2 to 6 months long. False Tr

ue
Computers and Technology
1 answer:
kompoz [17]3 years ago
6 0

Answer: False

Explanation:

Certification in Audio Engineering equips one with skills needed in the music industry such as being able to record, mix and master sounds as well as knowledge of studio equipment such as microphones, speakers, consoles and the computer software needed to blend all these components together.

As such, it can take a bit of time to learn it adequately enough to be certified.  This is why Technical colleges offer certifications in audio engineering through programs that usually last between 6 months and a year.

You might be interested in
For java
Sedbober [7]

Answer:

public class array{

    public static void main(String []args){

       int[] array = {2,4,7,1,9};

       int num_vals = array.length;

       for(int i=0;i<num_vals;i++){

           

           System.out.println(array[i] + " ");

       }

       for(int i=num_vals-1;i>=0;i--){

           

           System.out.println(array[i] + " ");

       }

    }

}

Explanation:

First create the class in the java programming.

Then create the main function and declare the array with values.

Store the size of array in num_vals variable by using the function array.length.

create a for loop to iterate the each element in the array and then print on the screen with spaces and newline.

it traverse the loop from first to last.

Then, again create the for loop to iterate the each element in the array and then print on the screen with spaces and newline but the traversing start from last to first.

8 0
3 years ago
I have six nuts and six bolts. Exactly one nut goes with each bolt. The nuts are all different sizes, but it’s hard to compare t
juin [17]

Answer:

Explanation:

In order to arrange the corresponding nuts and bolts in order using quicksort algorithm, we need to first create two arrays , one for nuts and another for bolts namely nutsArr[6] and boltsArr[6]. Now, using one of the bolts as pivot, we can rearrange the nuts in the nuts array such that the nuts on left side of the element chosen (i.e, the ith element indexed as nutArr[i]) are smaller than the nut at ith position and nuts to the right side of nutsArr[i] are larger than the nut at position "I". We implement this strategy recursively to sort the nuts array. The reason that we need to use bolts for sorting nuts is that nuts are not comparable among themselves and bolts are not comparable among themselves(as mentioned in the question)

The pseudocode for the given problem goes as follows:

// method to quick sort the elements in the two arrays

quickSort(nutsArr[start...end], boltsArr[start...end]): if start < end: // choose a nut from nutsArr at random randElement = nutsArr[random(start, end+1)] // partition the boltsArr using the randElement random pivot pivot = partition(boltsArr[start...end], randElement) // partition nutsArr around the bolt at the pivot position partition(nutsArr[start...end], boltsArr[pivot]) // call quickSort by passing first partition quickSort(nutsArr[start...pivot-1], boltsArr[start...pivot-1]) // call quickSort by passing second partition quickSort(nutsArr[pivot+1...end], boltsArr[pivot+1...end])

// method to partition the array passed as parameter, it also takes pivot as parameter

partition(character array, integer start, integer end, character pivot)

{

       integer i = start;

loop from j = start to j < end

       {

check if array[j] < pivot

{

swap (array[i],array[j])

               increase i by 1;

           }

 else check if array[j] = pivot

{

               swap (array[end],array[j])

               decrease i by 1;

           }

       }

swap (array[i] , array[end])

       return partition index i;

}

7 0
3 years ago
The ________ tier of the three-tier architecture consists of computers, phones, and other mobile devices that have browsers that
andrey2020 [161]

Answer:

It is the user tier of the 3-tier architecture that consists of computers, phones, and other mobile devices that have browsers that request and process web pages.

Explanation:

Almost if not all applications that use e-commerce for operations use the 3-tier architecture.  3-tier architecture is simply the arrangement of server tier which consists of all computers that run a web server and a database tier that consists of computers that run a DBMS to store and retrieve data. We also have the user data that consists of computers, phones, and other mobile devices that have browsers that request and process web pages.

When you make a request, for instance to Google in your local browser, the browser sends a request to the internet. This initial interaction between the user and the internet is what is known as the user tier of the 3 tier architecture. Basically, it is the phase where end users access content online through graphical interface browsers and make requests to the web servers and DBMS.

Learn more about 3-tier architecture

brainly.com/question/12627823

#LearnWithBrainly

6 0
3 years ago
Select the two true statements about functions with parameters:
kondor19780726 [428]

Answer:

Option (B) and (C) is the correct option to the following question.

Explanation:

Because the function is the module of the program and we call that function again and again anywhere whenever we need that function in the program.

Function is used to carry out any operation which is used in the program many times and it creates the program short and simple.

<u>For example</u>: if we need to add or multiply two numbers many times in the program then, we create one or two functions for addition and subtraction or one program for both, when we need them we call them.

4 0
3 years ago
Write a program that reads an unspecified number of integers, determines how many positive and negative values have been read, a
Viktor [21]

Answer:

The program to this question can be given as:

Program:

import java.util.*;

//import package for user input  

class Main     //define class

{

public static void main(String a[])  

//define main function

{

int positive_number=0,negative_number=0,count=0,num; //define variable

double total=0,avg=0;  

//creating Scanner class object.

Scanner ob = new Scanner(System.in);

System.out.println("Enter an integer, when done input 0: "); //message

num= ob.nextInt();

//taking input from user

if (num==0)  //check number equal to 0  

{  

System.out.println("No numbers are entered except 0"); //message

System.exit(1);

}

else

{

while (num!= 0)  

{    

   if (num> 0)

   {

positive_number++; // Increase positives

}

else

{

negative_number++; // Increase negatives

}

total=total+num; // Accumulate total

count++;    // Increase the count

num=ob.nextInt();

}

// Calculate the average

avg=total/count;

// Display values

System.out.println("The positive number is:"+positive_number);

System.out.println("The negatives number is:"+negative_number);

System.out.println("total is:"+total);

System.out.println("average is:"+avg);

}

}

}

Output:

Enter an integer, when done input 0: 22

2

1

4

0

The positive number is:4

The negatives number is:0

total is:29.0

average is:7.25

Explanation:

In the above program firstly we import the package for user input then we define a class that is main in this class we define the main method in the main method we define variable. Then we create a scanner class object for user input. In the number variable, we take multiple inputs from the user and also check that the user does not insert 0 at the starting of the program. To check this we use the condition statement that is a number equal to 0 then it will terminate the program. In the else part we first declare the loop that checks that inserted number is positive and negative and in this, we calculate the total of the numbers and at the end of the loop, we calculate the average of the number and print all the values.

4 0
3 years ago
Read 2 more answers
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