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Flauer [41]
3 years ago
8

Help me please I have no idea on how to do this. Thanks

Mathematics
1 answer:
andriy [413]3 years ago
6 0
1) P=2w +2l
46=2w +14
32=2w
16= w or width

2) A=lw
A=7 x 12
A= 84

3) A= 12 x 21
A= 252
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What are the coordinates of the endpoints of the midsegment for △XYZ that is parallel to XZ⎯⎯⎯⎯⎯ ?
Ksenya-84 [330]

The coordinates of the endpoints of the mid-segment of Δ XYZ that parallel to XZ are (1 , 6) and (1 , 3)

Step-by-step explanation:

In a triangle the segment which joining the mid points of two sides:

  • Parallel to the 3rd side
  • Its length is equal half the length of the 3rd side
  • It's called the mid-segment of the triangle

In Δ XYZ

∵ Vertex X is (0 , 7)

∵ Vertex Y is (2 , 5)

∵ Vertex Z is (0 , 1)

∵ The mid-segment of Δ XYZ is parallel to XZ

- The mid-segment intersects the other two sides of the Δ

  at their mid-points

∴ The mid-segment intersects XY and YZ at their midpoints

∴ The endpoints of the mid-segment are the midpoints of

   XY and YZ

The mid point of a segments whose endpoints are (x_{1},y_{1}) and (x_{2},y_{2}) is (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

∵ X = (0 , 7) and Y = (2 , 5)

∴ x_{1} = 0 and x_{2} = 2

∴ y_{1} = 7 and y_{2} = 5

∵ The mid point of XY = (\frac{0+2}{2},\frac{7+5}{2})

∴ The mid point of XY = (\frac{2}{2},\frac{12}{2})

∴ The mid point of XY = (1 , 6)

∵ Z = (0 , 1) and Y = (2 , 5)

∴ x_{1} = 0 and x_{2} = 2

∴ y_{1} = 1 and y_{2} = 5

∵ The mid point of ZY = (\frac{0+2}{2},\frac{1+5}{2})

∴ The mid point of ZY = (\frac{2}{2},\frac{6}{2})

∴ The mid point of ZY = (1 , 3)

∵ The endpoints of the mid-segment are the midpoints of

   XY and YZ

∴ The end points of the mid segments are (1 , 6) and (1 , 3)

The coordinates of the endpoints of the mid-segment of Δ XYZ that parallel to XZ are (1 , 6) and (1 , 3)

Learn more:

You can learn more about the mid-point in brainly.com/question/5223123

#LearnwithBrainly

7 0
3 years ago
Wren’s first display box is 6 inches long, 9 inches wide, and 4 inches high. What is the volume of the display box? Explain your
Black_prince [1.1K]

Answer:

\text{Volume of display box}=216\text{ in}^3    

Step-by-step explanation:

We have been given that Wren’s first display box is 6 inches long, 9 inches wide, and 4 inches high. We are asked to find the volume of display box.

We know that the box is in form of cuboid, so its volume would be length times width times height.

\text{Volume of display box}=6\text{ in}\times 9\text{ in}\times 4\text{ in}

\text{Volume of display box}=216\text{ in}^3

Therefore, the volume of the display box is 216 cubic inches.

7 0
3 years ago
Help Me For Brainlist !!!!!!!!!!!!
tatiyna

Answer:

30°,40°

Step-by-step explanation:

let the other angles be 3x and 4x

3x+4x+110=180

7x=180-110=70

x=70/7=10

3x=3×10=30

4x=4×10=40

5 0
3 years ago
Read 2 more answers
Please find the surface area
nevsk [136]
4*(10*12/2)+4*(12*9)+(12*12)= 816 ft^2

the surface area is 816 ft^2.
5 0
3 years ago
the surface areas of two similar solids are 1,008cm^2 and 1,372cm^2. the volume of the larger solid is 1,801cm^3. find the volum
Anni [7]
<span>Remember the ratios
Linear = a : b
Area = a^2 : b^2
Volume = a^3 : b^3

Hence area ratios are 1008 : 1372
Becomes linear ratios of Sqrt(1008) : sqrt(1372) :: 31.749 : 37.040
Volume ratios becomes 31.749^3 : 37.040^3 :: 32002.96 : 50817.46

Hence

32002.96 / 50817.46 = Vol (S) / 1801 cm^3
Vol(s) = 32002.96 X 1801 / 50817.46 = 1134.20cm^3 ( nearest hundredth).

</span>
8 0
3 years ago
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