Answer: the tuition in 2020 is $502300
Step-by-step explanation:
The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.
The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500
The fee in 2018 is the 19th term of the sequence. Therefore,
T19 = $45,4120
n = 19
Therefore,
454120 = 20500 + (19 - 1) d
454120 - 20500 = 19d
18d = 433620
d = 24090
Therefore, an
equation that can be used to find the tuition y for x years after 2000 is
y = 20500 + 24090(x - 1)
Therefore, at 2020,
n = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
I don’t see a expression...
Answer:
A. 247.03
Step-by-step explanation:
Answer: (0.8115, 0.8645)
Step-by-step explanation:
Let p be the proportion of people who leave one space after a period.
Given: Sample size : n= 525
Number of people responded that they leave one space. =440
i.e. sample proportion: 
z-score for 90% confidence level : 1.645
Formula to find the confidence interval :
Hence, a 90% confidence interval for the proportion of people who leave one space after a period: (0.8115, 0.8645)
