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2 years ago

What mix number is equivalent to 13/6

Mathematics

1 answer:

-BARSIC- [3]2 years ago

4 0

Answer:

2 1/6

Step-by-step explanation:

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Solve open parentheses square root of 7 close parentheses to the 6 x power = 49x−6.

LUCKY_DIMON [66]

(sqrt7)^6x = 49x - 6

There is no easy way to solve this . Drawing a graph will give a good approximation.

Draw y = (sqrt7)66x

and y = 49x - 6 and see where they intersect

Ill draw it on desmos graphing tool and give you the link.

7 0

3 years ago

Find f(x) - g(x) when f(x) = 2x^2 - 4x g(x) = x^2 + 6x

SOVA2 [1]

The last one 3x^ + 2x

7 0

2 years ago

What is the next term of the arithmetic sequence 1, -2, -5, -8, ...

Vaselesa [24]

Answer:

-11

Step-by-step explanation:

Subtract 3 everytime

3 0

2 years ago

Read 2 more answers

The output of an economic system Q, subject to two inputs, such as labor L and capital K, is often modeled by the Cobb-Dougl

Anna35 [415]

Answer:

Step-by-step explanation:

Given

Economic system Q is given by

$Q=cL^aK^b$

also $a+b=1$

if $Q=12,200$

$a=\frac{1}{6}$

$b=\frac{5}{6}$

$c=42$

substitute these values

$12,200=42\times (L)^{\frac{1}{6}}K^{\frac{5}{6}}$

$(L)^{\frac{1}{6}}K^{\frac{5}{6}}=\frac{12,200}{42}$

$K^{\frac{5}{6}}=\frac{12,200}{42(L)^{\frac{1}{6}}}$

$K=(\frac{12,200}{42})^{\frac{6}{5}}\times \frac{1}{L^{5}}$

differentiate w.r.t to L to get $\frac{dK}{dL}$

$\frac{dK}{dL}=(\frac{12,200}{42})^{\frac{6}{5}}\times (-5)\times L^{-6}$

$\frac{dK}{dL}=-5(\frac{12,200}{42})^{\frac{6}{5}}\times \frac{1}{L^6}$

$\frac{dK}{dL}=-\frac{4515.466}{L^6}$

6 0

3 years ago

A pool measuring 18 meters by 22 meters is surrounded by a path of uniform width. If the area of the pool and the path combined

suter [353]

Answer: the width of the uniform path is 9 meters.

Step-by-step explanation:

Let x represent the width of the uniform path.

A pool measuring 18 meters by 22 meters is surrounded by a path of uniform width. It means that the combined length of the pool and the uniform path is (18 + 2x) meters and the combined width of the pool and the uniform path is (22 + 2x) meters.

If the area of the pool and the path combined is 1440 square meters, it means that

(18 + 2x)(22 + 2x) = 1440

396 + 36x + 44x + 4x² = 1440

4x² + 80x + 396 - 1440 = 0

4x² + 80x - 1044 = 0

Dividing both sides of the equation by 4, it becomes

x² + 20x - 261 = 0

x² + 29x - 9x - 261 = 0

x(x + 29) - 9(x + 29) = 0

x - 9 = 0 or x + 29 = 0

x = 9 or x = 29

Since the width cannot be negative, then x = 9 meters

5 0

2 years ago