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Olegator [25]
3 years ago
10

The line y = x − 6 y=x−6 has exactly one point in common with the circle x 2 + y 2 = r 2 x2+y2=r2. what is the value of r 2 r2?

Mathematics
1 answer:
quester [9]3 years ago
7 0
Given:
y = x - 6         (1)
 for the line
x² + y² = r²     (2)
 for the circle

When the line intercepts the circle, the x and y values will be equal.
Equate the values of y by substituting (1) into (2).
x² + (x - 6)² = r²
x² + x² - 12x + 36 = r²
2x² - 12x + 36 = r²

Answer:  r² = 2x² - 12x + 36
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Please help me with the following questions. Thanks in advance!!
Orlov [11]

Answer:

Step-by-step explanation:

Eight

590 = 1800 e^(-0.4t)     Divide by 1800

0.32778 = e^(-0.4t)       Put the value for e in the denominator.

0.32778 = 1 / e^(0.4t)   Notice the sign's gone. Multiply both sides by e^(0.4t)

0.32778 *e^(0.4t) = 1    Divide by 0.32778

e^(0.4t) = 3.0508          Take the natural log of both sides.

0.4t = 1.11542                 Divide both sides by 0.4

t = 2.78855

You should put this in the original equation to see if it checks. It does.

=============================

Nine

3^(3 - 3x) + 6 = 42         Subtract 6 from both sides

3^(3 - 3x) = 36               Take the log of both sides.

(3 - 3x) ln(3) = ln 36

(3 - 3x) *1.098612 = 3.58352   Divide by 1.098612

3 - 3x = 3.26186             Subtract 3 from both sides

- 3x = 0.26186                 Divide by - 3

x = - 0.087287    

4 0
3 years ago
What are the solutions to this equation?
ziro4ka [17]

 

\displaystyle\\(x-4)^2=49\\\\(x-4)^2-49=0\\\\(x-4)^2-7^2=0\\\\(x-4-7)(x-4+7)=0\\\\(x-11)(x+3)=0\\\\x-11 = 0~~~\text{or}~~~x+3=0\\\\x-11=0~~~\implies~~~\boxed{x_1=11}\\\\x+3=0~~~\implies~~~\boxed{x_2=-3}\\\\\boxed{\bf The~solutions~are:~~x =11~~\text{or}~~x =-3}



8 0
3 years ago
The diagram shows a sector of a circle radius 10 cm. the angle is 135 degrees
Black_prince [1.1K]

Answer:

The perimeter is 43.6 cm

Step-by-step explanation:

In this question, we are tasked with calculating the perimeter of the sector.

Firstly, we define what a sector is. A sector is part of a circle which is is blinded by two radii and an arc. Hence we say a sector contains two radii.

Thus, to calculate the perimeter of the sector, we need the length of the arc added to 2 * length of the radius

Let’s calculate the length of the arc.

Mathematically, this is theta/360 * 2 * pi * r

where theta is the angle subtended at the middle of the circle which is 135 according to the question, and our radius is 10cm

Thus, we have

135/360 * 2 * 22/7 * 10 = 23.57 cm

Adding two radii to this, we have;

23.57 + 2(10)

= 23.57 + 20 = 43.57 = 43.6 cm to 1 decimal place

5 0
2 years ago
What is the standard form of this equation of a circle?
Olenka [21]
<span>x² + y² + 14x − 4y − 28 = 0

x² +14x +y² - 4y =28
x²+2*7x  +7² -7²  + y² - 2*2y +2² - 2² = 28
(x+7)² + (y-2)² -7²-2² =28
</span>(x+7)² + (y-2)²=28+49+4

(x+7)² + (y-2)² =81 is the answer.
5 0
2 years ago
Read 2 more answers
How do you factor x^3-2x^2-35x?
natima [27]
X^3 -2x^2 -35x

=x(x^2-2x-35)

=x(x-7)(x+5)
5 0
3 years ago
Read 2 more answers
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