If the length of JK is 16.4 miles, it will be diameter of this circle, the radius will be JK/2 = 8.2 miles
As we know the length of circle is 2π*r in this case r = 8.2
The arc JM is 1/4 length of the whole circle so arc JM = (2π*8.2)*(1/4) = 2π*8.2/4 = π*8.2/2 = π*4.1
if we assume that π=3.14 the answer will be 3.14 * 4.1 = 12.874.... And as the answer needs to be rounded to the nearest tenth it will be 12.874≈12.9
So the answer will be 12.9
3 3/4÷ 1/4
15/4÷1/4
15/4÷4/1
15*4=60
4*1=4
60/4=15
15 times 1/4 can fit into 3 3/4.
Answer:
w= 6
Step-by-step explanation:
I just started by making an educated guess using the values already given. Then I inserted that into the problem to see if it worked.
L= 2w - 5
I used 6 as a random, educated guess for the value of w.
L = 2(6) - 5
L = 12-5
L = 7
Then, multiply L by 2 to account for both side lengths of the rectangle.
7(2)= 14
Subtract that value from the total perimeter to find what the width must equal.
26 - 14 = 12
Divide that answer by 2 since there are two sides for width.
12/2 = 6
I know this was kind of long, but I hope it helps! :)
Step-by-step explanation:
Area of a trapezium = SOPS/2 × ph
Sops is the sum of 4+10 = <u>1</u><u>4</u>
14/2 is 7. 7×4 = <u>2</u><u>8</u>
<u>A</u><u> </u><u>=</u><u> </u><u>2</u><u>8</u><u>c</u><u>m</u><u>²</u>
Area = L×W
10×6= 60cm²
Answer:
m<1 = 118
Step-by-step explanation:
The remote angles theorem states that when one extends one of the sides of a triangle, the sum of the two non-adjacent angles is equal to the measure of the angle between the extension of the side and a side of a triangle. One can apply this theorem here by stating that
(28) + (90) = m<1
Remember, a box around an angle signifies that its measure is (90) degrees.
Solve this problem by performing the operation,
118 = m<1
