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irinina [24]
3 years ago
9

The sales tax rate for a local county is 8.5%. If an item costs $194 (before tax), how much sales tax will be due? Round answer

to the nearest penny
Mathematics
1 answer:
icang [17]3 years ago
6 0

\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{8.5\% of 194}}{\left( \cfrac{8.5}{100} \right)194}\implies 16.49

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Plz help ASAP will mark brainlist
Vlad [161]

Answer:

\huge \boxed{\mathrm{C}}

Step-by-step explanation:

The domain is the set of all possible values for x.

The function does not cross the line x = 1.

The domain is all real numbers except  1.

The range is the set of all possible values for y.

The function does not cross the line y = 0.

The range is all real numbers except 0.

8 0
3 years ago
Describe the sample space for each of these experiments (a) A coin is tossed and a single die is rolled. (b) A paper cup is toss
kondor19780726 [428]

Answer:

a) S={(head,1),(head,2),(head,3),(head,4),(head,5),(head,6),(tails,1),(tails,2),(tails,3),(tails,4),(tails,5),(tails,6)}

b) S={top,bottom,side}

c) S={(Ace of diamonds),(Two of diamonds),(Three of diamonds),(Four of diamonds),(Five of diamonds),(Six of diamonds),(Seven of diamonds), (Eight of diamonds),(Nine of diamonds),(Ten of diamonds), (Jack of diamonds), (Queen of diamonds), (King of diamonds), (Ace of hearts),(Two of hearts),(Three of hearts),(Four of hearts),(Five of hearts),(Six of hearts),(Seven of hearts), (Eight of hearts), (Nine of hearts),(Ten of hearts), (Jack of hearts), (Queen of hearts),(King of hearts),(Ace of clubs),(Two of clubs),(Three of clubs),(Four of clubs),(Five of clubs),(Six of clubs),(Seven of clubs), (Eight of clubs), (Nine of clubs),(Ten of clubs), (Jack of clubs),(Queen of clubs),(King of clubs),(Ace of spades),(Two of spades),(Three of spades),(Four of spades),(Five of spades),(Six of spades),(Seven of spades),(Eight of spades), (Nine of spades),(Ten of spades),(Jack of spades),(Queen of spades),(King of spades)}

Step-by-step explanation:

The sample space is all the possible outcomes from each experiment:

a) The sample has the pairs of the result of the coin (head or tails) and the dice (a number from 1 to 6):

S={(head,1),(head,2),(head,3),(head,4),(head,5),(head,6),(tails,1),(tails,2),(tails,3),(tails,4),(tails,5),(tails,6)}

b) A paper cup can land in three different ways, on its top, bottom or  side:

S={top,bottom,side}

c) The sample space is all the cards in the deck:

S={(Ace of diamonds),(Two of diamonds),(Three of diamonds),(Four of diamonds),(Five of diamonds),(Six of diamonds),(Seven of diamonds), (Eight of diamonds),(Nine of diamonds),(Ten of diamonds), (Jack of diamonds), (Queen of diamonds), (King of diamonds), (Ace of hearts),(Two of hearts),(Three of hearts),(Four of hearts),(Five of hearts),(Six of hearts),(Seven of hearts), (Eight of hearts), (Nine of hearts),(Ten of hearts), (Jack of hearts), (Queen of hearts),(King of hearts),(Ace of clubs),(Two of clubs),(Three of clubs),(Four of clubs),(Five of clubs),(Six of clubs),(Seven of clubs), (Eight of clubs), (Nine of clubs),(Ten of clubs), (Jack of clubs),(Queen of clubs),(King of clubs),(Ace of spades),(Two of spades),(Three of spades),(Four of spades),(Five of spades),(Six of spades),(Seven of spades),(Eight of spades), (Nine of spades),(Ten of spades),(Jack of spades),(Queen of spades),(King of spades)}

3 0
3 years ago
Plz help...do both plz
Gemiola [76]
The answer for number 4 is 13 and number 6 is 121 and the last problem for number 7 is 112
3 0
3 years ago
Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court
Ksju [112]

Answer:

(a)\dfrac{92}{117}

(b)\dfrac{8}{39}

(c)\dfrac{25}{117}

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed)=P(MW)+P(WM)

=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.
  • Two women are appointed

P(at least one woman is appointed)=P(MW)+P(WM)+P(WW)

P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}

In Part B, P(MW)+P(WM)=\frac{8}{39}

Therefore:

P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}

5 0
3 years ago
Ruth has a beaker containing a solution of 800 mL of acid and 200 mL of water. She thinks the solution is a little strong, so sh
NISA [10]

Answer:

350 mL of water

Step-by-step explanation:

Well she starts with 200mL of water and there is 800 mL of acid of water.

She drains 100 mL of acid and adds 100 mL of water so there is 300 mL of water.

And she stirs meaning the compounds have mixed.

Then she drains 100 mL and she they are mixed she drains half of acid and half of water so she has 250 mL of water.

The she adds 100 mL of water so now there’s 350 mL of water left.

3 0
3 years ago
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