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3 years ago

Peggy had three times as many quarters and nickels. she had $1.60 in all. How many nickels and how many quarters did she have?

Mathematics

2 answers:

USPshnik [31]3 years ago

8 0

I say the answer is D

makvit [3.9K]3 years ago

3 0

If she has 3 times as many quarters as nickels, and nickels are represented by n, you would multiply n by three to get your answer, so your answer is 3n, or D.

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What do I multiple to -1 1/7 to get 1

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Step-by-step explanation:

-1 1/7 is in improper fraction form -8/7

-8/7x = 1

x = -7/8

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2 years ago

If a set of exam scores forms a symmetrical distribution, what can you conclude about the students scores

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If a set of exam scores forms a symmetrical distribution, then the student mean scores is the median and the mode too.

<h3>What is a Symmetrical distribution?</h3>

A symmetrical distribution by definition is the situation which occurs when the values of variables appear at regular frequencies and is characterized by the mean, median, and mode all occuring at the same point in most cases.

Graphically, symmetrical distributions may appear as a normal distribution (i.e., bell curve).

Read more on Symmetrical distribution;

brainly.com/question/1422576

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1 year ago

A cereal box filling machine is designed to release an amount of 16 ounces of cereal into each box, and the machine’s manufactur

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Using the z-distribution, it is found that since the p-value is less than 0.05, there is evidence that the mean amount of cereal in each box is different from 16 ounces at 0.05 significance.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if the mean is not different to 16 ounces, that is:

$H_0: \mu = 16$

At the alternative hypothesis, it is tested if the mean is different, hence:

$H_1: \mu \neq 16$

<h3>What is the test statistic?</h3>

The test statistic is:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

$\sigma$ is the standard deviation of the population.

n is the sample size.

The parameters for this problem are:

$\overline{x} = 15.75, \mu = 16, \sigma = 1.46, n = 150$ .

Hence:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{15.75 - 16}{\frac{1.46}{\sqrt{150}}}$

z = -2.1

<h3>What is the p-value and the conclusion?</h3>

Using a z-distribution calculator, for a two-tailed test, as we are testing if the mean is different of a value, with z = -2.1, the p-value is of 0.0357.

Since the p-value is less than 0.05, there is evidence that the mean amount of cereal in each box is different from 16 ounces at 0.05 significance.

More can be learned about the z-distribution at brainly.com/question/16313918

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1 year ago