All categories

3 years ago

Peggy had three times as many quarters and nickels. she had $1.60 in all. How many nickels and how many quarters did she have?

Mathematics

2 answers:

USPshnik [31]3 years ago

8 0

I say the answer is D

makvit [3.9K]3 years ago

3 0

If she has 3 times as many quarters as nickels, and nickels are represented by n, you would multiply n by three to get your answer, so your answer is 3n, or D.

You might be interested in

Mrs. Lavetan has 45 to complete her writing paper. She spend 10 and 1/8 min to planning her paper and 15 and 1/2 minutes weighti

Flura [38]

Answer: 20 minutes

Step-by-step explanation:

She has 45 mins to complete her writing paper.

She spends: $10\frac{1}{8}$ minutes to plan her paper.

She spends: $15\frac{1}{2}$ minutes writing rough drafts.

How much time left does she have?

$45-(10\frac{1}{8} +15\frac{1}{2})$

$45-(10+15(\frac{1}{8}+\frac{1}{2}))$

$45-(25\frac{(1)(2)+(8)(1)}{(8)(2)})$

$45-(25\frac{2+8}{16} )$

$45-(25\frac{10}{16})$ Simplify the fraction.

$45-(25\frac{5}{8})$

$45-25(\frac{5}{8})$

So she has approximately,

$20\frac{5}{8} =\frac{165}{8}= 20$ minutes.

8 0

3 years ago

Sam scored 36 marks out of 60.Express the marks in percentage

Pani-rosa [81]

Answer:

60%

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Find the missing side. Round to the nearest tenth.

Vikki [24]

183 is the answer to that

3 0

2 years ago

Please help Cant figure it out

IrinaVladis [17]

Answer:

Step-by-step explanation:

If a number is to the power of a negative number, then it is just that number's reciprocal: e.g. y⁻ˣ = $\frac{1}{y^{x} }$

Therefore, m⁻² will be m² in the denominator, as n⁻³ will be n³ in the numerator.

That will look like $\frac{3n^{3} }{5m^{2} }$ .

So, that is C.

3 0

3 years ago

NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z

Roman55 [17]

Answer:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

Step-by-step explanation:

Given system of equations:

$\begin{cases}y=x^2-9\\y=4x-4\end{cases}$

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

$\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}$