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2 years ago

Question : What were the 15 routines of reactions you clic at home?

Geography

1 answer:

barxatty [35]2 years ago

5 0

This question is incomplete. Here's the complete question.

During the months of lockdown, what were the 5 routines or reactions you did at home?

Answer:

I started to sleep late, working, and studying through the night instead of the day.
I watched a lot of cooking shows because I find them soothing.
I started exercising indoors, following online classes, instead of going out for a run.
I learned to cook a lot better!
I rediscovered the joy of playing with my dog.

Explanation:

During the months of lockdown, going outside became dangerous, so we all had to change our daily routines. We all may have developed new routines, trying to keep a sense of normality.

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3 years ago

Read 2 more answers

2 1. Scattering cross-section of acrosol particles is 2.5E-12 m , absorption cross-section is 0.45E- .2 12 m Concentration of pa

Alona [7]

Answer:

$T = 3.23 \times 10^{-83}$

Explanation:

thickness of aerosol layer is 2.5 km

zenith angle is 40 degree

we know that

$\tau = \epsilon_{ext} . h$

where

$\epsilon_{ext} = N.\sigma_{ext}$

$\epsilon_{ext}$ is extinction coefficient

$\sigma_{ext}$ extiction cross section

N = Concentration

$\sigma_{ext} = (2.5 + 0.45)\times 10^{-12} m^2$

$= 2.95 \times 10^{-12} m^2$

$\epsilon_{ext} = 2\times 10^7 \times 2.95 \times 10^{-12} m^2 \times m^{-3}$

$= 5.9 \times 10^{-5} m^{1}$

$\tau = 5.9 \times 10^{-5} m^{-1} \times 2.5\times 10^3 m$

$= 14.75\times 10^{-2}$

transimiitance $T = e^{\frac{-\tau}{\mu}}$

$T = e^{\frac{- 14.75 \times 10^{-2}}{cos 40}}$

$T = 3.23 \times 10^{-83}$

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3 years ago

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