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LiRa [457]
3 years ago
8

There are 12 runners in a race. In how many ways can these runners place first , second, and third?

Mathematics
2 answers:
lisov135 [29]3 years ago
5 0
The correct answer should be B
bonufazy [111]3 years ago
3 0
Answer is C 220. because there are 12 runners
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What is the volume if this rectangular prism: 5/2 cm by 3/4 cm by 1/3 cm
aleksley [76]

Answer:

5/8 cm

Step-by-step explanation:

5/2*3/4=15/8

15/8*1/3=15/24=5/8

7 0
3 years ago
Read 2 more answers
Between June 2017 and June 2018, the price of gasoline increased by 25%. If the price
WARRIOR [948]

Answer:

$2.4

Step-by-step explanation:

2018 June               2017June                    

125                            100

1                                 0.75

Therefore,  3= 100x3/125

=300/125

=$2.4

hope it helps:D

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6 0
2 years ago
There are 850 employees at a software company. The company’s CEO was interested in finding out if his employees prefer the new c
mixas84 [53]

Answer: B & E

i just took it

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A computer training institute has 625 students that are paying a course fee of $400. Their research shows that for every $20 red
Anastasy [175]
1.
If no changes are made, the school has a revenue of :

625*400$/student=250,000$

2.
Assume that the school decides to reduce n*20$.

This means that there will be an increase of 50n students.

Thus there are 625 + 50n students, each paying 400-20n dollars.

The revenue is: 

(625 + 50n)*(400-20n)=12.5(50+n)*20(20-n)=250(n+50)(20-n)

3.

check the options that we have, 

a fee of $380 means that n=1, thus 

250(n+50)(20-n)=250(1+50)(20-1)=242,250   ($)


a fee of $320 means that n=4, thus

 250(n+50)(20-n)=250(4+50)(20-4)=216,000    ($)


the other options cannot be considered since neither 400-275, nor 400-325 are multiples of 20.

Conclusion, neither of the possible choices should be applied, since they will reduce the revenue.
6 0
3 years ago
What is the probability that a randomly selected permutation of the letters A, A, C, C, L, L, O, R, T, U would spell "calculator
kirill [66]

Answer:

See explanation

Step-by-step explanation:

Total number of letters = n! = 10

Permutation for 10 letters = n!

                                          = 10!

                                          = 10*9*8*7*6*5*4*3*2*1

                                          = 3628800

From n letters:

Number of A = 2

Number of C = 2

Number of  L = 2

A₁, A₂, C₁, C₂, L₁, L₂, O, R, T, U

Out of 3628800 permutations the word calculator can be spelled as:

C₁ A₁ L₁ C₂ U L₂ A₂ T O R

C₂ A₂ L₂ C₁ U L₁ A₁ T O R

and so on

So total number of different permutations are  

(permutation of number of letters) / permutation of (number of As * number of Cs * number of Ls)

  =  10! / (2! 2! 2 !)  

  = 10*9*8*7*6*5*4*3*2*1 / (2*1) (2*1) (2*1)

  = 3628800 / 2 * 2 * 2

  =  3628800 / 8

  =   453600

Hence probability that a randomly selected permutation of the letters A, A, C, C, L, L, O, R, T, U would spell "calculator" is:

 1 / total number of different permutations  

= 1 / 10! / (2! 2! 2 !)  

= 1/453600

= 0.000002

8 0
3 years ago
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