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LiRa [457]
3 years ago
8

There are 12 runners in a race. In how many ways can these runners place first , second, and third?

Mathematics
2 answers:
lisov135 [29]3 years ago
5 0
The correct answer should be B
bonufazy [111]3 years ago
3 0
Answer is C 220. because there are 12 runners
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With a real machine, why is W out always smaller than W in
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3 years ago
Help ASAP its due today!
Genrish500 [490]

Answer:

The answer is D) 60

Step-by-step explanation:

4 0
1 year ago
Read 2 more answers
Which of the following points is a solution of y > Ixl + 5?
Step2247 [10]

Answer:

B. (1,7)

Step-by-step explanation:

We can substitute the x and y values of each coordinate into the inequality and test if they work.

Let's start with A, 5 being y and 0 being x .

5 > |0|+5\\5> 0+5\\5 > 5

5 IS NOT greater than 5, they are the exact same, so A is out.

Let's try B, 1 being x and 7 being y.

7 > |1| + 5\\7 > 1 + 5\\7 > 6

7 IS greater than 6, so B. (1,7) does work for this inequality!

Let's do C for fun, when 7 is x and 1 is y.

1 > |7| + 5\\1>7+5\\1>12

1 IS NOT greater than 12, it is quite less than 12, so C doesn't work.

Therefore B. (1,7) works for the inequality of y > |x|+5.

Hope this helped!

7 0
2 years ago
5.
nikitadnepr [17]

Answer:

i am not so sure but I think its 10x = 33

3 0
2 years ago
At noon, ship A is 180 km west of ship B. Ship A is sailing east at 35 km/h and ship B is sailing north at 25 km/h. How fast is
weeeeeb [17]

Answer:

Step-by-step explanation:

Gotta love these motion  problems!!! This one  is especially tricky!  At noon, ship A is 180 km west of ship B.  If ship A is traveling east, it is closing its distance to ship B (if ship B didn't move).  But ship B is moving north at the same time.  We need to find the distance each can travel in 4 hours using the d = rt formula.  For ship A.  We know it's moving at 35 km/h, so in 4 hours it can move d = 35(4) which is 140 km.  Remember that is closing the distance to ship B.  So it is 180 - 140 directly south of ship B.  This problem will turn out to be a right triangle problem of sorts.  The distance of 40 km serves as the base of this right triangle.  

With ship B moving north at 25 km/hr, it can travel d = 25(4) which is 100 km.  This serves as the height of the triangle.  We are asked to find the rate at which the distance is changing 4 hours from their starting points.  We know how far each can travel in those 4 hours, so in order to find the rate of change (which is the same thing as the slope!), we take the height and divide it by the base because that is the same thing as taking the rise over the run.  100/40 is 10/4 which is a rate of change of 2.5 km/hr

5 0
2 years ago
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