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Fudgin [204]
3 years ago
12

Among the rights you have as a user of computing resources is the right to​ _______.

Computers and Technology
2 answers:
Zinaida [17]3 years ago
4 0

Answer:

C) protection from​ viruses, worms, and other threats

Explanation:

Your obligations include:

  • You should follow the standard techniques for using applications.
  • You should only report important and relevant problems.
  • You should use your mobile following your organization's guidelines and not at free will.
  • You should treat your password very seriously.

You are entitled to be protected from viruses, worms, and other threats  when you use your computing resources.

Ivanshal [37]3 years ago
3 0
Protection from​ viruses, worms, and other threats
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Xelga [282]

Answer:

b they have high sensitivity to surrounding sound

Explanation:

tell me it's correct or not

if it's correct so I hope it is helpful for you

but no so I am sorry

6 0
2 years ago
Read 2 more answers
What can be can be considered data
gavmur [86]

Answer:

The amount of data you use while talking on a phone is a form of data.

Explanation:

8 0
3 years ago
AirPods se están despintando al ponerlos en quitaesmalte ayudaaaa?
slega [8]

Answer:

In reality, a diluted type of acetone that dissolves plastics and coating is Nail polish removers.

Explanation:

The chemical composition of the material has permanently changed, nothing else than if you had shot it. No repair but replacement is available.

Acetone does not get along with plastics.

This classic timelapse video shows just how cheap plastic acetone is.

When it's out, I have my new AirPods Pro. I got a odd smell when I opened the box when I received it. The little one is solid and chemical. It's new, I guess, and after days it will be gone.

But after ten days of use it doesn't. And the smell remains strong. It won't go quickly, I believe.

Instead I noticed that the smell is often shaping the silicone tips.

About 8 hours a day I use this AirPods Pro. Is it possible for a long time to use this smelling tip?

Actually, I must say they are soft and work well for noise cancelation, I love this silicone tip. If the strange smell doesn't hurt. To me, that's good.

6 0
3 years ago
The birthday paradox says that the probability that two people in a room will have the same birthday is more than half, provided
poizon [28]

Answer:

The Java code is given below with appropriate comments for explanation

Explanation:

// java code to contradict birth day paradox

import java.util.Random;

public class BirthDayParadox

{

public static void main(String[] args)

{

   Random randNum = new Random();

   int people = 5;

   int[] birth_Day = new int[365+1];

   // setting up birthsdays

   for (int i = 0; i < birth_Day.length; i++)

       birth_Day[i] = i + 1;

 

   int iteration;

   // varying number n

   while (people <= 100)

   {

       System.out.println("Number of people: " + people);

       // creating new birth day array

       int[] newbirth_Day = new int[people];

       int count = 0;

       iteration = 100000;

       while(iteration != 0)

       {

           count = 0;

           for (int i = 0; i < newbirth_Day.length; i++)

           {

               // generating random birth day

               int day = randNum.nextInt(365);

               newbirth_Day[i] = birth_Day[day];

           }

           // check for same birthdays

           for (int i = 0; i < newbirth_Day.length; i++)

           {

               int bday = newbirth_Day[i];

               for (int j = i+1; j < newbirth_Day.length; j++)

               {

                   if (bday == newbirth_Day[j])

                   {

                       count++;

                       break;

                   }

               }

           }

           iteration = iteration - 1;

       }

       System.out.println("Probability: " + count + "/" + 100000);

       System.out.println();

       people += 5;

   }

}

}

4 0
3 years ago
Given two 2x3 (2 rows, 3 columns) arrays of integer , x1 and x2, both already initialized , two integer variables , i and j, and
Gnesinka [82]
JAVA programming was employed...

What we have so far:
* Two 2x3 (2 rows and 3 columns) arrays. x1[i][j] (first 2x3 array) and x2[i][j] (second 2x3 array) .
* Let i = row and j = coulumn.
* A boolean vaiable, x1rules

Solution:

for(int i=0; i<2; i++)
{
   for(int j=0; j<3; j++)
   {
      x1[i][j] = num.nextInt();
   }
}// End of Array 1, x1.

for(int i=0; i<2; i++)
{
   for(int j=0; j<3; j++)
   {
      x2[i][j] = num.nextInt();
   }
}//End of Array 2, x2
This should check if all the elements in x1 is greater than x2:

x1rules = false;
if(x1[0][0]>x2[0][0] && x1[0][1]>x2[0][1] && x1[0][2]>x2[0][2] && x1[1][0]>x2[1][0] && x1[1][1]>x2[1][1] && x1[1][2]>x2[1][2])
{
   x1rules = true;
   system.out.print(x1rules);
}
else
{
   system.out.print(x1rules);
}//Conditional Statement
7 0
3 years ago
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