Answer:
Following are the answer to this question:
Explanation:
Prototypical inheritance:
This inheritance is a part of the object-oriented programming, in the JavaScript, the prototype is also an instance of an entity, on this type of inheritance an object inherits another object directly, in which an instance could be composed of several sources which enable simple selective inheritance and a flat structure of delegation[[Prototype]].
Web accessibility using JavaScript:
In the website or web page, JavaScript is usually fully accessible if another script 's implementation has been device-independent, and the components are accessible to be used in assistive devices. It enables the developers to improve web page information, which helps in communication, data processing, and regulation, and it also helps in management.
Answer: AWS CodeCommit
Explanation:
The AWS service that the developers can use to meet the requirements that are illustrated in the question is the AWS CodeCommit.
The AWS CodeCommit is refered to as a fully-managed source control service which can be used in the hosting of Git-based repositories which are secure.
AWS CodeCommit makes it easy for the collaboration on code for teams in a secure ecosystem. CodeCommit can securely store binaries, source code etc.
2000 nibbles I think correct me if I’m wrong
Answer:
This is not a good solution
Explanation:
Your web browser uses port 80 outgoing to make web requests, so if you’re blocking incoming port 80, all you’re blocking is users of the organization from connecting to the internet. You have indeed close a vulnerable port to access from hackers, but this also can reduce the productivity of the organization.
Answer:
a) the average CPI for machine M1 = 1.6
the average CPI for machine M2 = 2.5
b) M1 implementation is faster.
c) the clock cycles required for both processors.52.6*10^6.
Explanation:
(a)
The average CPI for M1 = 0.6 x 1 + 0.3 x 2 + 0.1 x 4
= 1.6
The average CPI for M2 = 0.6 x 2 + 0.3 x 3 + 0.1 x 4
= 2.5
(b)
The average MIPS rate is calculated as: Clock Rate/ averageCPI x 10^6
Given 80MHz = 80 * 10^6
The average MIPS ratings for M1 = 80 x 10^6 / 1.6 x 10^6
= 50
Given 100MHz = 100 * 10^6
The average MIPS ratings for M2 = 100 x 10^6 / 2.5 x 10^6
= 40
c)
Machine M2 has a smaller MIPS rating
Changing instruction set A from 2 to 1
The CPI will be increased to 1.9 (1*.6+3*.3+4*.1)
and hence MIPS Rating will now be (100/1.9)*10^6 = 52.6*10^6.
