1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alona [7]
3 years ago
11

20liters of mixture contain milk nad water in the ratio 5:3 if 4liters of the mixture are replaced by 4 liters of milk find the

new ratio of milk to water
Mathematics
1 answer:
Finger [1]3 years ago
5 0

Answer:

the new ratio milk/water is  14:6  or 7:3

Step-by-step explanation:

milk/water=5/3

milk +water=5+3=8

ratio of milk=5/8  and ratio of water=3/8

if 4 liter removed from mixture then: 20=4= 16 liter

the amount of milk in 16 liter=16*5/8=10 liter of milk

the amount of water in 16 liter=16*3/8= 6 liter

add 4 liter of milk to the mixture: 10+4=14 liter of milk and 6 liter of water

the new ratio milk/water is  14:6  or 7:3

You might be interested in
5 hours 8 min - 3 hours 12 min
belka [17]
Hello,

Here is your answer:

The proper answer is "2.68".

First translate the question:

5 hours and 8 min=5.8

3 hours 12 min=3.12

Now subtract:

5.8-3.12=2.68

Your answer is 2.68!

If you need anymore help feel free to ask me!

Hop this helps!
6 0
3 years ago
I JUST NEED #13 please and thnx
emmainna [20.7K]

\bf \cfrac{18}{32}\implies \cfrac{2\cdot 3\cdot 3}{2\cdot 2\cdot 2\cdot 2\cdot 2}\implies \cfrac{3\cdot 3}{2\cdot 2\cdot 2\cdot 2}\implies \boxed{\cfrac{9}{16}}\qquad \checkmark \\\\[-0.35em] ~\dotfill\\\\ \cfrac{27}{48}\implies \cfrac{3\cdot 3\cdot 3}{2\cdot 2\cdot 2\cdot 2\cdot 3}\implies \cfrac{3\cdot 3}{2\cdot 2\cdot 2\cdot 2}\implies \boxed{\cfrac{9}{16}}\qquad \checkmark

3 0
3 years ago
Emma spent $38.22 on 3 dozen bagels and a gallon of iced tea. The price of the gallon of iced tea was $5.25. The following equat
Masja [62]
3d + $5.25 = $38.22
3d= $38.22-$5.25
= $32.97
d= 32.97/3
=$10.99

a dozen of bagels costs $10.99
6 0
3 years ago
Write an equation in standard form for the line that passes through the given points.
Agata [3.3K]

So, pretend this is your x-axis and y-axis:

                                   I

        I

   (-2,7) •  I

        I

        I       • (2, 5)

        I

        I

        I  

        I

 _________________I____________________

        I

        I

        I

TO GET FROM POINT (-2, 7) TO POINT (2, 5), WE MOVE DOWN 2 AND OVER 4, SO THE SLOPE IS -1/2. IF WE FOLLOW THAT SLOPE AND MOVE DOWN 1 AND OVER 2 FROM THE FIRST POINT OF  (-2, 7), WE WILL LAND ON A POINT LOCATED AT (0, 6), WHICH WOULD BE THE "Y-INTERCEPT". WE WERE JUST ABLE TO CALCULATE THE SLOPE OF THE LINE AND THEN USE THE SLOPE TO FIND THE INTERCEPT. SO, THE "SLOPE-INTERCEPT" FORM OF THE EQUATION FOR THIS LINE IS:

y = -1/2x + 6

TO RE-WRITE THIS IN STANDARD FORM, WE JUST WANT TO MOVE THE X VARIABLE OVER TO THE LEFT WITH THE Y VARIABLE, SO:

y = -1/2x + 6

+1/2x   + 1/2x

1/2x + y = 6 .... and that is your answer!

8 0
2 years ago
Two problems here I need solved! I need every step, so please have that with your answers!!
Free_Kalibri [48]
QUESTION 1

We want to solve,

\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}

We factor the denominator of the fraction on the right hand side to get,

\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.

This implies
\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.

\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}

We multiply through by LCM of
(x-4)(x - 2)

(x - 2) + x(x-4) = 2

We expand to get,

x - 2 + {x}^{2} - 4x= 2

We group like terms and equate everything to zero,

{x}^{2} + x - 4x - 2 - 2 = 0

We split the middle term,

{x}^{2} + - 3x - 4 = 0

We factor to get,

{x}^{2} + x - 4x- 4 = 0

x(x + 1) - 4(x + 1) = 0

(x + 1)(x - 4) = 0

x + 1 = 0 \: or \: x - 4 = 0

x = - 1 \: or \: x = 4

But
x = 4
is not in the domain of the given equation.

It is an extraneous solution.

\therefore \: x = - 1
is the only solution.

QUESTION 2

\sqrt{x+11} -x=-1

We add x to both sides,

\sqrt{x+11} =x-1

We square both sides,

x + 11 = (x - 1)^{2}

We expand to get,

x + 11 = {x}^{2} - 2x + 1

This implies,

{x}^{2} - 3x - 10 = 0

We solve this quadratic equation by factorization,

{x}^{2} - 5x + 2x - 10 = 0

x(x - 5) + 2(x - 5) = 0

(x + 2)(x - 5) = 0

x + 2 = 0 \: or \: x - 5 = 0

x = - 2 \: or \: x = 5

But
x = - 2
is an extraneous solution

\therefore \: x = 5
7 0
4 years ago
Other questions:
  • mason wants to play with maliyah's doll house but first he needs to stop at the clubhouse. if all three stops are in the shape o
    8·2 answers
  • Help ????????????????????
    5·1 answer
  • Help me plzzzz!!! On number 1
    15·1 answer
  • A bag contains 5 blue marbles, 6 red marbles, and 7 green marbles. two random marbles are drawn, one at a time without replaceme
    11·1 answer
  • I really need help some one please
    11·1 answer
  • Central Park is a rectangular park in New York City. A map of Central Park in New York City. The measured length is 12.5 centime
    14·1 answer
  • From 5 a.m. to noon, the temperature rose 15 °F to a high of 10 °F.
    5·1 answer
  • Find the lower quartile of 12, 16, 22, 34, 66, 73
    15·1 answer
  • What is the midpoint for 3.818
    12·2 answers
  • Number 13. Multiply please.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!