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Effectus [21]
3 years ago
15

During one day at an office, one-half of the amount of money in the petty drawer was used in the morning, and one-third of the r

amining money was used in the afternoon, leaving $6 in the petty cash drawer at the end of the day. How much was in the petty cash drawer at the start of the day?
Mathematics
2 answers:
tekilochka [14]3 years ago
8 0
Answer:
$2 is two-thirds of the money in the box.
So after the morning $3 was in the box.
That was half of what was there to start, $6.
Paha777 [63]3 years ago
4 0

Answer:

idk you tell me

Step-by-step explanation:

1. you should tell me

2. i write the answer when you tell me

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Write the following as an equation. Amy is 16 yrs older than Peter, whose age is 'x' yrs. 6 yrs ago, her age was twice Peter's a
azamat
Amy's current age is 16 years greater than Peter's age, so Amy's current age is equal to x + 16.

6 years ago, Amy's age was equal to twice that of Peter's age at that point, so her age was 2(x - 6).

As currently her age is x + 16 then 6 years ago her age was x + 16 - 6, which is x + 10.

As 6 years ago her age was equal to 2(x - 6) and x  + 10, we can see that x + 10 = 2(x - 6).
5 0
3 years ago
Thanks for helping, I really appreciate it
den301095 [7]

Answer:

a)ΔFHA is similar to ΔZIA by hypotenuse side test.

reason:- angle H and angle I are of 90 degrees.

b) FH/ ZI = HA/ IA = FA/ ZA

angle F = angle Z, angle H = angle I , angle angle A = angle A

The scale factor is 3/2......( HA/IA = 12/8 = 3/2)

c) IZ = 3.3 ....( FH/ IZ = 3/2, 5/ IZ = 3/2, IZ = 10/3 = 3.33)

7 0
3 years ago
Bonsoir vous pouvez m’aider alors : A la masse x (en g) d’un objet suspendu , on associe la longueur (en mm) d’un ressort . Cett
natita [175]

Answer:

50 g = 95mm

60 g = 98 mm

0 g = 98/60 = 1.63 mm Step-by-step                                                      explanation:hope this help y'all

8 0
3 years ago
R - 9S = 2 3R - 3S = -10
GrogVix [38]
R-9s=2  add 9s to both sides

r=2+9s  making 3r-3s=-10 become:

3(2+9s)-3s=-10  perform indicated multiplication on left side

6+27s-3s=-10  combine like terms on left side

6+24s=-10  subtract 6 from both sides

24s=-16  divide both sides by 24

s=-16/24

s=-2/3, making r-9s=2 become:

r-9(-2/3)=2  perform indicated multiplication on left side

r+6=2 subtract 6 from both sides

r=-4

So s= -2/3 and r= -4
8 0
3 years ago
12)What is the resistance of a 600-foot #12 (solid) aluminum conductor? Hint: The resistance of the conductor is 3.18 Ohms/1000
Butoxors [25]

Answer:

1.91 Ohms

Step-by-step explanation:

It is given that the resistance of the conductor is 3.18 Ohms/1000 feet.

It means that the resistance of the 1000-foot conductor is 3.18 Ohms.

So, the resistance of the 600-foot #12 (solid) aluminium conductor is \frac{600}{1000} (3.18)

= 6 × 0.318

= 1.908

= 1.91 Ohms (rounded to two decimal places)

6 0
3 years ago
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