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Brilliant_brown [7]
4 years ago
10

Please solve this problem ! Show your work of how you solved it ! Please answer this !!

Mathematics
1 answer:
kow [346]4 years ago
6 0

Answer:

7a+1

Step-by-step explanation:

Okay so what you are supposed to do is simplify that for your answer. How you do this is by circling the things in common. So for example "4a" and "3a" are in common, so 4a plus 3a is 7a. Now look at the next things in common which would be "-5" and "6" add those together and you get 1.

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Could anyone help me out, it’s would mean a lot.
SIZIF [17.4K]

Answer:

x = 19

Step-by-step explanation:

If two lines are perpendicular, they create 4 90° angles. Meaning, in this case, that m<DBC = 90 and m<DBA = 90.

We're given that m<DBE = 2x - 1 and that m<CBE = 5x - 42.

The sum of angles DBE and CBE = m<DBC = 90°

We can add the two angles and set it equal to 90 to find x

2x - 1 + 5x - 42 = 90\\7x - 43 = 90\\7x = 133\\x = \frac{133}{7} =19

6 0
4 years ago
The distance on the number line from -10 to -2 equals 5x – 12. What is the value of x?
Troyanec [42]

It would be: - 2 - (-10) = 5x - 12

= -2 + 10 = 5x - 12

= 8 + 12 = 5x

= x = 20 / 5

= x = 4

4 0
4 years ago
If AB = 8 and BC = 24, then AC =<br><br> If AB = 17 and AC = 68, then BC =
Kryger [21]

Answer:

(i) The length of AC is 32 units, (ii) The length of BC is 51 units.

Step-by-step explanation:

(i) Let suppose that AB and BC are collinear to each other, that is, that both segments are contained in the same line. Algebraically, it can be translated into this identity:

AC = AB + BC

If we know that AB = 8 and BC = 24, then:

AC = 8 + 24

AC = 32

The length of AC is 32 units.

(ii) Let suppose that AB and AC are collinear to each other, that is, that both segments are contained in the same line. Algebraically, it can be translated into this identity:

AC = AB + BC

BC = AC - AB

If we know that AC = 68 and AB = 17, then:

BC = 68-17

BC = 51

The length of BC is 51 units.

6 0
4 years ago
Is the following a rational or irrational number:<br><br> 0.7077077707777…
HACTEHA [7]

Answer:it following number is irrational

Step-by-step explanation:

8 0
3 years ago
If a+b+c=16 and a^2+b^2+c^2=90 then find the value a^3+b^3+c^3-3abc
grin007 [14]

(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)\\(16)^2=90+2(ab+bc+ca)\\256-90=2(ab+bc+ca)\\166/2=ab+bc+ca\\83=ab+bc+ca\\a^3-b^3-c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)\\(a+b+c)(a^2+b^2+c^2-(ab+bc+ca))\\16(90-(83))\\16(7)\\=112

3 0
3 years ago
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