So hmmm there are 5pennies in a nickel, and 10pennies in a dime and 25pennies in a quarter
now, in $6.10, there are 610 pennies
n = amount of nickels coins
d = amount of dime coins
q = amount of quarter coins
so... we know, there are 5*n or 5n pennies in the nickels, and 10*d or 10d pennies in the dimes and 25*q or 25q in the quarter coins, and we know their sum is 610 pennies total, thus
5n + 10d + 25q = 610
now, there are 4 more "n" then "d", so whatever "d" is, "n" is 4 more than that
n = d + 4
and twice as many "q" than "n", so, whatever "n" is, then
q = 2n
solve for "d", to see how many dimes are there
what about the nickels? well, n = d + 4
what about the quarters? well, q = 2d + 8
They all don’t care when I say peecock
But when I say poopcock everyone stairs
We know that
the <span>formula of the arithmetic series is
</span>Sn=<span>n[2(a1) + (n - 1)d]/2
where
Sn=80
n=20
d=2
a1=?
then
80=20*[2*a1+19*2]/2----------------> </span>160=[40*a1+760]
160=[40*a1+760]----------> a1=(160-760)/40------------> a1=-15
<span>
the answer is
a1=-15
</span>
Answer:
the circumference decreases by a factor 1/3.
Step-by-step explanation:
You need to use PEMDAS
So first you do the parenthesis.
8*1=8.
So now re-write the problem.
50+10*8+2
Now you are going to multiply.
10*=80
Now re-write the problem again.
10+80+2
10+80=90+2=92
So the answer to this problem is 92.