Let p (x) = 4x^4-13x^2-2x
The zero of x-2 is 2
putting x = 2 in p (x), we get,
p (2) = 4×2^4-13×2^2-2×2
= 64 - 52 - 4
= 64 - 56
= 8
Therefore, remainder = 8
<span>–1 + 6(–1 – 3x) > –39 – 2x.
</span>-1-6-18x>-39-2x
-7-18x>-39-2x
-18x>-32-2x
-16x>-32
x<2
B. x<2
Answer:
Options (A), (B) and (C)
Step-by-step explanation:
In the given figure,
Length of side AD = 16 units
If this side is scaled by a factor = k
Then the length of the corresponding side will be = 16k
If 0 < k < 1,
Then length of the corresponding side will be less than 16.
[Example: If k = 
Therefore, scaled side of the corresponding side of the quadrilateral =
= 4]
That means length of corresponding sides may be 4, 6.5 and 12.
Options (A), (B) and (C) will be the answer.
Answer:
Step-by-step explanation to be honest probably 12 if not i’m so sorry
Answer:
Step-by-step explained
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