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3 years ago

-3x^2-8x+7 help please

Mathematics

1 answer:

ale4655 [162]3 years ago

8 0

For this equation we are factoring. When you do this. You get the answer of:

(-3x²+8x-7)

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Maya decided to paint some of the rooms in her hotel. She found out that a room required 3/2 cans of paint. If Maya buys 9 cans

Dmitry [639]

Answer:

She can paint <u>6 rooms</u>.

Step-by-step explanation:

Given:

Maya decided to paint some of the rooms in her hotel. She found out that a room required 3/2 cans of paint.

If Maya buys 9 cans of paint.

Now, to find the rooms she can paint.

So, we use unitary method to get the number of rooms:

If, $\frac{3}{2}$ cans of paint is needed to paint 1 room.

Then, 1 can of paint is needed to paint = $\frac{1}{\frac{3}{2}} =\frac{2}{3}$ room.

Thus, 9 cans of paint is needed to paint = $\frac{2}{3} \times 9$

$=\frac{18}{3} \\\\=6\ rooms.$

Therefore, she can paint 6 rooms.

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3 years ago

Solving for a Confidence Interval: Algebra 2 points possible (graded) In the problems on this page, we will continue building th

baherus [9]

Answer:

Step-by-step explanation:

1) The given inequality is

$|\sqrt{n} \frac{(\bar R_n-p)}{\sqrt{p(1-p)} } |$

$\to n( \bar R _n - p)^2$

$\to n\bar R +np^2-2nR_np$

Arranging the terms with p² and p, we get

$p^2(n+q^2_{\alpha /2)-p(2n \bar R _n+q^2_{\alpha / 2})+n \bar R ^2 _n$

Hence, the inequality is of the form

Ap² + Bp + c < 0

2. A quadratic equation of the form

Ap² + Bp + c < 0 with A > 0 looks like

<u>Check the attached image</u>

The region where the values are negative lies between p₁ and p₂ ...

The p₁ < p < p₂

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3 years ago

Answer these questions please: You don't need to plot the point just answer B & C. Also every single coordinate plane is lik

Nady [450]

Step-by-step explanation:

When moving left, subtract from the x-coordinate and when moving right, add in the x-coordinate. When moving down, subtract from the y-coordinate and when moving up, add in the y-coordinate.

1) Given point = (0, 0). 3 units right and 4 units down means (0+3, 0-4) = (3, -4).

2) Given point = (5, 2). 4 units left and 2 units down means (5-4, 2-2) = (1, 0).

3) Given point = (-6, -1). 8 units right and 5 units up means (-6+8, -1+5) = (2, 4).

4) In Quadrant II, the x-coordinate is negative and the y-coordinate is positive. So taking R = (-6,6). 2 units right and 6 units down means (-6+2, 6-6) = (-4, 0).

5) In Quadrant IV, the x-coordinate is positive and the y-coordinate is negative. So taking R = (6,-6). 7 units left and 4 units up means (6-7, -6+4) = (-1, -2).

5 0

4 years ago

382.993 is the nearest hundredth

julsineya [31]

382.99 is rounded to the nearest hundredth

8 0

3 years ago

Read 2 more answers

I need help very fast thank you

MrMuchimi

A=[y/(x-3)^2]+[1/(x-3)^2]
Hope this helps!

5 0

4 years ago