All categories

3 years ago

Use all 2,4,6,8 Once and any operation and brackets to find two equations that equal 24

Mathematics

1 answer:

Genrish500 [490]3 years ago

7 0

Answer:

It is given that by using 2,4,6,8 once and any operation and brackets we have to make two equations which is equal to 24.

1. [8×6]÷(4-2)=48÷2=24 [ First multiplied 8 and 6 keeping them in a bigger bracket then divided by (4-2=2) by keeping it in a single smaller bracket.

2. [8×4]- (6+2)=32 -8=24 [Multiply 8 and 4 and then subtract (6+2=8) from it.This is equal to 24.

These are the two equations that i wrote for you , you can find many more by yourself.

You might be interested in

Simplify and solve this equation for q: 3q + 5 + 2q – 5 = 65.

gladu [14]

3q+5+2q-5 = 65

5q = 65

q = 13

3 0

3 years ago

I don’t know how to do the hole page

FrozenT [24]

#7
20%•$300
$60
300-60
240
Hope this helps!!

8 0

3 years ago

The 7% sales tax on a new $32,000 car.<br>

Rama09 [41]

Answer:

$34,240

Step-by-step explanation:

7% of $32,000 is $2,240

$32,000+$2,240=$34,240

6 0

3 years ago

Wyatt has 32 marbles in his collection. Twenty of his marbles are red, four are blue, and the

dmitriy555 [2]

Answer:

6 and 2/5

Step-by-step explanation:

20% of 32 is 6.4

4 0

3 years ago

A coin is tossed and a single 6 sided number cube is rolled. Find the probability of landing on the heads side of the coin and r

Delicious77 [7]

Answer:

The probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

Step-by-step explanation:

Given:

Coin is tossed and a single 6 sided number cube is rolled.

Let the event of tossing head be 'H' and event of rolling a 3 be 'R3'.

Now, we know that:

Probability of an event 'A' = Favorable outcomes of 'A' ÷ Total possible outcomes

Now, for tossing a coin, the total possible outcomes are head and tail. So, there are 2 possible outcomes.

So, probability of event 'H' is given as:

$P(H)=\dfrac{n(H)}{n(S)}\\\\P(H)=\frac{1}{2}=0.5$

Similarly, for rolling a 6 sided cube, the possible outcomes are numbers 1 to 6. So, the number of possible outcomes is, $n(S)=6$

Now, probability of rolling a 3 is given as:

$P(R3)=\frac{n(R3)}{n(S)}\\\\P(R3)=\frac{1}{6}$

Now, both the events 'H' and 'R3' occur together. So, the combined probability is the product of two individual probabilities as they are independent events. So,

$P(H\ and\ R3)=P(H)\times P(R3)\\\\P(H\ and\ R3)=\frac{1}{2}\times \frac{1}{6}\\\\P(H\ and\ R3)=\frac{1}{12}=0.083$

Note: Independent events are those events whose intersection is an empty set of events or the outcome of one event doesn't affect the outcome of the other event.

Therefore, the probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

4 0

3 years ago