Use all 2,4,6,8 Once and any operation and brackets to find two equations that equal 24

Mathematics

1 answer:

Genrish500 [490]3 years ago

7 0

Answer:

It is given that by using 2,4,6,8 once and any operation and brackets we have to make two equations which is equal to 24.

1. [8×6]÷(4-2)=48÷2=24 [ First multiplied 8 and 6 keeping them in a bigger bracket then divided by (4-2=2) by keeping it in a single smaller bracket.

2. [8×4]- (6+2)=32 -8=24 [Multiply 8 and 4 and then subtract (6+2=8) from it.This is equal to 24.

These are the two equations that i wrote for you , you can find many more by yourself.

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Simplify the expression (x^3- 5x^2 + 7x - 12) ÷ (x – 4) using long division

Kisachek [45]

Answer:

${x}^{2} - x + 3$

Step-by-step explanation:

Instead, since the divisor is in the form of $x - c$ , use what is called Synthetic Division. Remember, in this formula, $-c$ gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:

4| 1 −5 7 −12

↓ 4 −4 12

_______________

1 −1 3 0 → ${x}^{2} - x + 3$

You start by placing the $c$ in the top left corner, then list all the coefficients of your dividend [x³ - 5x² + 7x - 12]. You bring down the original term closest to $c$ then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an ${x}^{2}$ , the −1 [ $x$ ] follows right behind it, and bringing up the rear, comes the 3, giving you the quotient of ${x}^{2} - x + 3$ .