Answer:
Step-by-step explanation:
R = 9x + 8y
4 = 9x + 8*8
4 = 9x + 64
Subtract 64 from both sides
4 - 64 = 9x + 64 - 64
-60 = 9x
Divide both sides by 9
-60/9 = 9x/9
-20/3 = x
x = -6 2/3
1) -10x+y=4
Now, you should substitute x in every situation.
* x=-2 <em>=> -10*(-2)+y=4... 20+y=4... <u>y=-16</u></em>
<em />* x=-1 =>-10*(-1)+y=4... 10+y=4... <u>y=-6</u>
<u />*x=0 => -10*0+y=4... <u>y=4</u>
<u />* x=1 => -10*1+y=4... -10+y=4... <u>y=14</u>
<u />* x=2 => -10*2+y=4... -20+y=4... <u>y=24</u>
<u>2)</u> -5x-1=y
For example: x=0
-5*0-1=-1
<u>
</u>
It’s too small zoom in some I will be glad to assist you
We know that imaginary roots always come in pairs, so we already know 4 solutions
-2, 2, 4 + i and a pair of 4 + i
Since imaginary roots always come in pairs we wont have more than 2 imaginary roots, since its a fifth degree root and we can only have 5 roots
So for sure, we will have 3 real roots and 2 imaginary roots
Last option, f(x) has three real roots and two imaginary roots