A and b are legs
a^2+b^2=c^2
lets say
a>b
so
a=13+3b
c=14+3b
a^2+b^2=c^2
(13+3b)^2+b^2=(14+3b)^2
9b^2+78b+169+b^2=9b^2+84b+196
10b^2+78b+169=9b^2+84b+196
minus 9b^2 both sides
b^2+78b+169=84b+196
minus 84b both sides
b^2-6b+169=196
minus 196 both sides
b^2-6b-27=0
factor
(b+3)(b-9)=0
set to zero
b+3=0
b=-3, false, dimentions cannot be negative
b-9=0
b=9
shorter leg is 9
a=13+3b
a=13+3(9)
a=13+27
a=40
c=14+3b
c=14+27
c=41
side legnths are
9in, 40in, 41in
Answer:
150
Step-by-step explanation:
Answer:
a. 144 cubic foot
b. 12 ft
c. 18 ft
Step-by-step explanation:
Let the volume of prism A be V_a
and that of prism b be V_b
ATQ, V_a + V_b= 432
also V_a= 0.5 V_b
⇒1.5 V_b= 432
= V_b= 432/1.5= 288 cubic feet
therefore V_a= 144 cubic feet
volume of prism= area of base×height = V_a
24×h = 144
⇒h= 12 ft
A_b= 2/3×24
⇒base area of prism B= 16 sq.ft
now 16×h_b= 288⇒h_b= 288/16= 18 ft
a12 * p78 = 936ap
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