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2 years ago

Thr four angles of a quadrilateral L are in the ratio 5:2:3:8find the angle

2 answers:

5 0

Ratio = 5:2:3:8
Sum of all internal angles = 360°
5x + 2x + 3x + 8x = 360°
18x = 360°
x = 20°
Therefore,
5x = 100°
2x = 40°
3x = 60°
8x = 160°
5:2:3:8 :: 100:40:60:160.

Simora [160]2 years ago

3 0

Answer:

100 : 40: 60: 160

Step-by-step explanation:

The angles of a quadrilateral add up to 360

If the ratio of angles are 5:2:3:8, multiply each by x

5x : 2x: 3x: 8x These are the angles in the quadrilateral

5x+2x+3x+8x = 360

Combine like terms

18x =360

Divide by 18

18x/18 = 360/18

x =20

To find the angles of the quadrilateral, we can substitute for x

5x : 2x: 3x: 8x

5*20: 2*20: 3*20: 8:20

100 : 40: 60: 160

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2 years ago

Scott and Letitia are brother and sister. After dinner, they have to do the dishes, with one washing and the other drying. They

ehidna [41]

Answer:

The probability that Scott will wash is 2.5

Step-by-step explanation:

Given

Let the events be: P = Purple and G = Green

$P = 2$

$G = 3$

Required

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If Scott washes the dishes, then it means he picks two spoons of the same color handle.

So, we have to calculate the probability of picking the same handle. i.e.

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

This gives:

$P(G_1\ and\ G_2) = P(G_1) * P(G_2)$

$P(G_1\ and\ G_2) = \frac{n(G)}{Total} * \frac{n(G)-1}{Total - 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{3-1}{5- 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{2}{4}$

$P(G_1\ and\ G_2) = \frac{3}{10}$

$P(P_1\ and\ P_2) = P(P_1) * P(P_2)$

$P(P_1\ and\ P_2) = \frac{n(P)}{Total} * \frac{n(P)-1}{Total - 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{2-1}{5- 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{1}{4}$

$P(P_1\ and\ P_2) = \frac{1}{10}$

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

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$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

$P(Same) = \frac{3}{10} + \frac{1}{10}$

$P(Same) = \frac{3+1}{10}$

$P(Same) = \frac{4}{10}$

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8 0

2 years ago

Draw the image of the following segment after a dilation centered at the origin with a scale factor of 2/3

Irina18 [472]

Answer:

Step-by-step explanation:

Let the ends of the given segment are A and B.

Coordinates of A → (8, 6)

Coordinates of B → (12, 12)

If a point (x, y) is dilated by a scale factor 'k' about the origin, rule to be followed,

(x, y) → (kx, ky)

If k = $\frac{2}{3}$

(x, y) → $(\frac{2}{3}x, \frac{2}{3}y)$

By this rule coordinates of the image points of A and B will be,

A(8, 6) → $A'(\frac{2\times 8}{3},\frac{2\times 6}{3})$

→ A'(5.3, 4)

B(12, 12) → $B'(\frac{12\times 2}{3}, \frac{12\times 2}{3})$

→ B'(8, 8)

Now we can get the image of segment AB after dilation by a scale factor of $\frac{2}{3}$ .

5 0

2 years ago