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Luda [366]
3 years ago
8

Write your question here (Keep it simple and clear to get the best answer) If jun has 12 T-shirt 6 pairs of parts, and 3 pairs o

f share, how many possibilities can be'drace himself up for the day?
Mathematics
1 answer:
Talja [164]3 years ago
7 0

Answer:

the number of possibilities that can be drace himself up for the day is 216

Step-by-step explanation:

Given that

jun has 12 t-shirts,6 pairs of pants and 3 pairs of shoes

We need to find out the possibilities that can be drace himself up for the day

So here

= 12C_1 \times  6C_1 \times  3C_1\\\\= \frac{12!}{1!(12 - 1)!}  \times \frac{6!}{1!(6 - 1)!} \times \frac{3!}{1!(3 - 1)!}\\\\= \frac{12!}{1!(11)!} \times  \frac{6!}{1!(5)!} \times  \frac{3!}{1!(2)!}\\\\= 12 \times 6 \times 3\\\\= 216

Hence, the number of possibilities that can be drace himself up for the day is 216

The same would be considered and relevant too

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