Answer:
y = (x - 7) + 4
Step-by-step explanation:
4 more = + 4
difference = (-)
y = (x - 7) + 4
Answer:
BC = 26
Step-by-step explanation:
since B is the midpoint of AC, then AB = BC
AC = 8x - 20 & AB = 3x - 1
AC = AB + BC or 2AB
8x - 20 = 2(3x - 1)
8x - 20 = 6x - 2
subtract 6x form each side
2x - 20 = -2
add 20 to each side
2x - 20 + 20 = -2 + 20
2x = 18
x = 9
BC = 3x - 1
BC = 27 - 1
BC = 26
AC = 52
Answer:
x = 45
Step-by-step explanation:
Solution:
x - y = 30
x - 15 = 30 ( y = 15 given)
x = 30 + 15
Therefore, x = 45
PLEASE MARK ME AS BRAINLIEST!!!
ALSO DON'T FORGET TO CHECK OUT THIS BLOG WHICH TEACHES YOU SMALL SCIENCE CONCEPTS EVERYDAY AND DONT WORRY ITS ABSOLUTELY FREE AND ITS REALLY BRIEF CONCEPTS:
ITS CALLED dynamicscience
Answer:
This type of transformation is a horizontal stretch.
<em></em>
Step-by-step explanation:
Given
Required
Determine the type of transformation
The first function can be expressed as:
While the second function is:
Solving f(0.5x), we have to substitute 0.5x for x in
So:
The second function is:
<em>This type of transformation is a horizontal stretch.</em>
<em></em>
<em>i.e. f(x) stretched to g(x)</em>
<span>1. a sine curve with amplitude 2, and period 4pi radians
</span>
the general equation of the sine curve ⇒⇒ y = a sin (nθ)
where: a is the amplitude and n = 2π/perid
∵ <span>amplitude 2, and period 4pi radians
</span>
∴ y = 2 sin (θ/2)
The correct answer is option D. y = 2 sin (θ/2)
===========================================
<span>2.The period and amplitude of the function ⇒⇒ y = 5 cos 2θ
</span>
<span>comparing with y = a cos nθ
</span>
where : a is the amplitude and n = 2π/period
<span>amplitude = 5 , period = 2π/n = 2π/2 = π
</span>
The correct answer is option B. Period: pi radians: Amplitude:5
============================================================
3. tan (2π/3) = tan 120° = -√3
120° lie in the second quadrant and its reference angle = 180° - 120° = 60°
tan function in the second quadrant is negative
∴ tan 120° = - tan 60 = -√3
The correct answer is C. -sqrt3
=====================================================
4. <span>Tan 5π/6 = tan 150° = -(√3)/3
</span>
150° lies in the second quadrant and its reference angle = 180° - 150° = 30°
tan function in the second quadrant is negative
∴ tan 150° = - tan 30 = -(√3)/3
The correct answer is <span>B.-sqrt3/3</span>