All categories

3 years ago

I need help with this one I don’t understand

Mathematics

1 answer:

adelina 88 [10]3 years ago

6 0

Answer:

C 27:12

Step-by-step explanation:

9:4x3=27:12

A ratio will keep the same factors.

So 1:2- 2:4 its basically a fraction.

You might be interested in

Show that √(1-cos A/1+cos A) =cosec A - cot A

Gennadij [26K]

Hi there!

$\sqrt{\frac{1-cosA}{1+cosA}} =$

We can begin by multiplying by its conjugate:

$\sqrt{\frac{1-cosA}{1+cosA}} * \sqrt{\frac{1+cosA}{1+cosA}} = \\\\\sqrt{\frac{(1-cosA)(1 + cosA)}{(1+cosA)(1 + cosA)}} =$

Simplify using the identity:

$1 - cos^2A = sin^2A$

$\sqrt{\frac{(1-cos^2A)}{(1+cosA)^2}} =\\\\\sqrt{\frac{(sin^2A)}{(1+cosA)^2}} =$

Take the square root of the expression:

${\frac{sinA}{1+cosA} =$

Multiply again by the conjugate to get a SINGLE term in the denominator:

${\frac{sinA}{1+cosA} * {\frac{1-cosA}{1-cosA} =\\$

Simplify:

${\frac{sinA(1-cosA)}{1-cos^2A} =$

Use the above trig identity one more:

${\frac{sinA(1-cosA)}{sin^2A} =$

Cancel out sinA:

${\frac{(1-cosA)}{sinA} =$

Split the fraction into two:

${\frac{1}{sinA} - \frac{cosA}{sinA} =$

Recall:

$1/sinA = cscA\\\\cosA/sinA = cotA$

Simplify:

$\frac{1}{sinA} + \frac{cosA}{sinA} = \boxed{cscA - cotA}$

5 0

2 years ago

Part I

klemol [59]

It depends on the shape it may be rotation

6 0

3 years ago

The endpoints of PQ are (4,1) and Q(4,8)

tatuchka [14]

Answer:

Search this up on google to find out what the answer is because no one is going to know how to do it.

5 0

4 years ago

What is the slope of the line shown below ?

ElenaW [278]

Answer:

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(6-(-2))/(3-1)

m=(6+2)/(2)

m=8/2

m=4

7 0

3 years ago

Need Help question is in the photo.

san4es73 [151]

Answer:D,E

Step-by-step explanation:

9/3=3

36=9×4

3 0

3 years ago