We have to calculate the probability of, a person chosen at random prefers pizza given that they are female, i.e $P(\text{Pizza}\ |\ \text{female})$

This is a conditional probability.

We know that,

$P(A\ |\ B)=\dfrac{P(A\ \cap\ B)}{P(B)}$

So,

$P(\text{Pizza}\ |\ \text{Female})=\dfrac{P(\text{Pizza}\ \cap\ \text{Female)}}{P({\text{Female}})}$

From the table,

$P(\text{Pizza}\ \cap\ \text{Female)}=\dfrac{119}{1000}$

$P({\text{Female}})=\dfrac{530}{1000}$

Putting the values,

$P(\text{Pizza}\ |\ \text{Female})=\dfrac{P(\text{Pizza}\ \cap\ \text{Female)}}{P({\text{Female}})}=\dfrac{\frac{119}{1000}}{\frac{530}{1000}}=0.225$

8 0

3 years ago

If 18 percent VAT is included in the price

natta225 [31]

Answer:

the formula is VAT %op cp ×13500 do that using this formul6 is should correct

4 0

3 years ago

8. 37.5 ÷2.5 , can y'all please help me with this one and I'm Soo close to getting an 100

kari74 [83]

Answer:

Step-by-step explanation:

37.5÷2.5 goes in 15 times

3 0

3 years ago

Read 2 more answers

2. ANSWER=

mixas84 [53]

Answer:

a yes udjwjwjwjwjwjwjwjwjw

yes men es chef

6 0

3 years ago