Question

In which region of its domain is.the function y=x^2-4 decreasing

Answer 1

Answer:

${b}^{2} - 4ac = 0 - 4 \times 1 \times ( - 4) = 16$

$\sqrt{16} = 4$

$\frac{ - b}{2a} = \frac{0}{2} = 0$

$\frac{ - 4}{4} = - 1$

it is decreasing from negative infinity to 0