3 years ago

0.07 is a smallest fraction?

Mathematics

1 answer:

Vinvika [58]3 years ago

8 0

0.07 is 7/100 (that is the simplest fraction)

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Expand:<br><img src="https://tex.z-dn.net/?f=f%28z%29%20%3D%20%20%5Cfrac%7B1%7D%7Bz%28z%20-%202%29%7D%20" id="TexFormula1" title

Monica [59]

Expand f(z) into partial fractions:

$\dfrac1{z(z-2)} = \dfrac12 \left(\dfrac1{z-2} - \dfrac1z\right)$

Recall that for |z| < 1, we have the power series

$\displaystyle \frac1{1-z} = \sum_{n=0}^\infty z^n$

Then for |z| > 2, or |1/(z/2)| = |2/z| < 1, we have

$\displaystyle \frac1{z-2} = \frac1z \frac1{1 - \frac2z} = \frac1z \sum_{n=0}^\infty \left(\frac 2z\right)^n = \sum_{n=0}^\infty \frac{2^n}{z^{n+1}}$

So the series expansion of f(z) for |z| > 2 is

$\displaystyle f(z) = \frac12 \left(\sum_{n=0}^\infty \frac{2^n}{z^{n+1}} - \frac1z\right)$

$\displaystyle f(z) = \frac12 \sum_{n=1}^\infty \frac{2^n}{z^{n+1}}$

$\displaystyle f(z) = \sum_{n=1}^\infty \frac{2^{n-1}}{z^{n+1}}$

$\displaystyle \boxed{f(z) = \frac14 \sum_{n=2}^\infty \frac{2^n}{z^n} = \frac1{z^2} + \frac2{z^3} + \frac4{z^4} + \cdots}$

6 0

2 years ago

If a whole pan of brownies is being sold for $16, how much it cost to purchase 3/4<br> of the pan?

KATRIN_1 [288]

Answer:

$12

Step-by-step explanation:

We have to do this operation:

(16/4) x 3 = 4 x 3 = $12

5 0

3 years ago

Read 2 more answers

How do you simplify this equation <br>-2÷2/3=

azamat

"you use "PEMDAS"

2*3 = 6

6/-2 =

-3

8 0

3 years ago

Round 355,668 to the nearest hundred thousands

Flura [38]

Answer:

400,000

Step-by-step explanation:

7 0

3 years ago

A sales representative from a local radio station is trying to convince the owner of a small fitness club to advertise on her st

statuscvo [17]

Answer:

Its D because its the initial number of members in da club. 1.02 is the rate of growth in each month.

Step-by-step explanation:

5 0

3 years ago