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sladkih [1.3K]
3 years ago
11

2. The path of a high diver is given by y = + (2x2 – 9x – 56), where y is the height of the diver

Mathematics
1 answer:
timofeeve [1]3 years ago
7 0

Answer:

The diver will be 8 feet from the end of the board when he hits the water.

Step-by-step explanation:

The diver hits the water when y = 0.

To find the distance, we have to find the values of x when y = 0.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = (x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this problem, we have that:

y = 2x^{2} - 9x - 56

2x^{2} - 9x - 56 = 0

So

a = 2, b = -9, c = -56

Then

\bigtriangleup = b^{2} - 4ac = (-9)^{2} - 4*2(-56) = 529

x_{1} = \frac{-(-9) + \sqrt{529}}{2*2} = 8

x_{2} = \frac{-(-9) - \sqrt{529}}{2*2} = -3.5

It is a horizontal distance, so the answer is a positive value.

The diver will be 8 feet from the end of the board when he hits the water.

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