Explanation:
Since {v1,...,vp} is linearly dependent, there exist scalars a1,...,ap, with not all of them being 0 such that a1v1+a2v2+...+apvp = 0. Using the linearity of T we have that
a1*T(v1)+a2*T(v1) + ... + ap*T(vp) = T(a1v19+T(a2v2)+...+T(avp) = T(a1v1+a2v2+...+apvp) = T(0) = 0.
Since at least one ai is different from 0, we obtain a non trivial linear combination that eliminates T(v1) , ..., T(vp). That proves that {T(v1) , ..., T(vp)} is a linearly dependent set of W.
This is Pythagorean's Theorem, with one leg being 10 and the hypotenuse being 16. Using those values in the theorem looks like this:
and
and
so
Take the square root of both sides to find that b = 12.5
54=.9x Solve for x. x=54/.9=60
Answer: 9 (with a margin of: 0)
Step-by-step explanation:
Times everything by 5
That gives you 15 + 10w = 105.
Subtract 15 from both sides
Divide by 10 to get w by itself
Then you solve
