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3 years ago

Using pemdas please

Mathematics

2 answers:

adell [148]3 years ago

7 0

Answer:

Step-by-step explanation:

5²= 10

10x3=30

90-30=60

Blizzard [7]3 years ago

4 0

Hello!

Let’s look at the acronym PEMDAS:

P - parentheses

E - exponents

M - muliplication

D - division

A - addition

S - subtraction

Now we can apply this order of operations to the given equation. Because there are no parentheses, we begin by simplifying the exponents:

90 - 5² x 3

90 - 25 x 3

Now we can move on to multiplication:

90 - 25 x 3

90 - 75

Finally, we can skip down to subtraction:

90 - 75

Using PEMDAS order of operations, the correct answer is 15.

I hope this helps!

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Romashka-Z-Leto [24]

Answer:

the anwer is 14-2294-dhi2

Step-by-step explanation:

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2 years ago

Find the area of the shape. Either enter an exact answer in terms of pi or use 3.14 for pi and enter your answer as a decimal.

Darya [45]

Answer:

314

Step-by-step explanation:

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2 years ago

A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he

UkoKoshka [18]

Answer:

a) The minimum sample size is 601.

b) The minimum sample size is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

We dont know the true proportion, so we use $\pi = 0.5$ , which is when we are are going to need the largest sample size.

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

a. If a 95% confidence interval with a margin of error of no more than 0.04 is desired, give a close estimate of the minimum sample size that will guarantee that the desired margin of error is achieved. (Remember to round up any result, if necessary.)

This is n for which M = 0.04. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.04\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.04}$

$(\sqrt{n})^2 = (\frac{1.96*0.5}{0.04})^2$

$n = 600.25$

Rounding up

The minimum sample size is 601.

b. If a 95% confidence interval with a margin of error of no more than 0.02 is desired, give a close estimate of the minimum sample size necessary to achieve the desired margin of error.

Now we want n for which M = 0.02. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}$