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Vinvika [58]
3 years ago
9

What is the equation of the line that passes through the point (-2,0) and has a slope of -2?

Mathematics
1 answer:
WARRIOR [948]3 years ago
6 0

Answer:

y=-2x-4

Step-by-step explanation:

y-y1=m(x-x1)

y-0=-2(x-(-2))

y-0=-2(x+2)

y=-2x-4+0

y=-2x-4

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Find the product of the expression:<br> (5p^3) (-1m^8p^2)
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Answer:

We conclude that:

  • \left(5p^3\right)\:\left(-1m^8p^2\right)=-5p^5m^8

Step-by-step explanation:

Given the expression

\left(5p^3\right)\:\left(-1m^8p^2\right)

Apply the rule:

a\left(-b\right)=-ab

so the expression becomes

\left(5p^3\right)\left(-1\cdot \:m^8p^2\right)=-5p^3\cdot \:1\cdot \:m^8p^2

Apply the rule:

a^b\cdot \:a^c=a^{b+c}

so the expression becomes

                             =-5p^{3+2}\cdot \:1\cdot \:m^8         ∵ p^3p^2=p^{3+2}

                             =-5p^5\cdot \:1\cdot \:m^8

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Therefore, we conclude that:

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