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qaws [65]
3 years ago
5

In a mathematics class, half of the students scored 87 on an achievement test. With the exception of a few students who scored 5

2, the remaining students scored 71. Which of the following statements is true about the distribution of scores?
Mathematics
1 answer:
Arisa [49]3 years ago
7 0

Answer:the mean is greater than the median

Step-by-step explanation:

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What is the product?<br> 3x[-6 -14 -11 -9]
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3 years ago
AP CALC 98 POINTS!!!!!!
bekas [8.4K]

Looking at this question again, I don't understand why you're told "for y=11". That doesn't seem relevant at all... So you can disregard the answer I posted a few minutes ago on your other question.

a) With x^2=-2+y+5\cos y, differentiate both sides with respect to x to get

2x=\dfrac{\mathrm dy}{\mathrm dx}-5\sin y\dfrac{\mathrm dy}{\mathrm dx}

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x}{1-5\sin y}

b) The point P occurs at x=2, which corresponds to a y-coordinate of

4=-2+y+5\cos y\implies y\approx4.928

The slope of the line tangent to this point is approximately

\dfrac{\mathrm dy}{\mathrm dx}\approx\dfrac{2(2)}{1-5\sin(4.928)}\approx0.68

so the equation of the tangent line is approximately

y-4.928=0.68(x-2)\implies y=0.68x+3.57

c) The tangent line to the graphed curve is vertical when \dfrac{\mathrm dy}{\mathrm dx} is undefined. This happens when 1-5\sin y=0, or y=\pi-\sin^{-1}\dfrac15+2n\pi and y=\sin^{-1}\dfrac15+2n\pi where n is any integer.

In case you're not sure where the general solution came from: We have

\sin y=\dfrac15

which has an infinite number of solutions. \sin^{-1}\dfrac15 is one of them, which we obtain by taking the inverse sine of both sides of this equation. Since \sin(\pi-x)=\sin x, we also know that \pi-\sin^{-1}\dfrac15 is a solution. And since \sin(x+2n\pi)=\sin x for integers n, we also know that we can add any multiple of 2\pi to these two solutions to get infinitely more solutions.

3 0
3 years ago
What is the area model of 9.63 ×3
lora16 [44]
The area is 28.89. I hope this helps you out!
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3 years ago
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