1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kirill [66]
3 years ago
11

Can someone explain me this

Mathematics
1 answer:
Pani-rosa [81]3 years ago
7 0
Multiply 9 x 5 and then whatever 9 x 5 was divide that into 270 and that's your answer
You might be interested in
What is the value for y
Klio2033 [76]
Hey there,

I believe but I'm not quite sure, I believe that the correct answer would be 42 because by subtracting 79-37, that should give you y.

Hope this helps. (forgive any errors.)

~Jurgen
6 0
3 years ago
Read 2 more answers
Helpp!!!!!! <br> What is X?
ANEK [815]

Answer:

(6,4)

Step-by-step explanation:

Not sure if that right hope it helps

7 0
2 years ago
Read 2 more answers
What fraction of a circle does the angle run through?
vladimir2022 [97]

Answer:

1/360

Step-by-step explanation:

4 0
3 years ago
Which of the following could be points on the unit circle: A. (4/3, 4/5) B. (5/13, 12/13)
IRINA_888 [86]

Answer:

Option (2) and (4) are correct.

(\frac{5}{13},\frac{12}{13} ) and  (\frac{6}{7},\frac{\sqrt{13}}{7} ) are points on the unit circle.

Step-by-step explanation:

Given : Some points of circles.

We have to choose which points could be points on the unit circle.

We know, the equation of circle is

x^2+y^2=r^2  ..........(1)

where r is radius of circle.

We check each point for x and y values on the equation of circle and see which point gives radius = 1

Thus,

1) (\frac{4}{3},\frac{4}{5} )

Put  in LHS of  (1) , we have,

(\frac{4}{3})^2+(\frac{4}{5})^2

Simplify, we have,

=\frac{16}{9}+\frac{16}{25}

=\frac{544}{225}\neq 1

Thus,  (\frac{4}{3},\frac{4}{5} ) is not a point on the unit circle.

2) (\frac{5}{13},\frac{12}{13} )

Put  in LHS of  (1) , we have,

(\frac{5}{13})^2+(\frac{12}{13})^2

Simplify, we have,

=\frac{25}{169}+\frac{144}{169}

=\frac{169}{169}= 1

Thus, (\frac{5}{13},\frac{12}{13} ) is a point on the unit circle.

3) (\frac{1}{3},\frac{2}{3} )

Put  in LHS of  (1) , we have,

(\frac{1}{3})^2+(\frac{2}{3})^2

Simplify, we have,

=\frac{1}{9}+\frac{4}{9}

=\frac{5}{9}\neq 1

Thus,  (\frac{1}{3},\frac{2}{3} ) is not a point on the unit circle.

4)  (\frac{6}{7},\frac{\sqrt{13}}{7} )

Put  in LHS of  (1) , we have,

(\frac{6}{7})^2+(\frac{\sqrt{13}}{7})^2

Simplify, we have,

=\frac{36}{49}+\frac{13}{49}

=\frac{49}{49}= 1

Thus,  (\frac{6}{7},\frac{\sqrt{13}}{7} ) is a point on the unit circle.

Thus, (\frac{5}{13},\frac{12}{13} ) and  (\frac{6}{7},\frac{\sqrt{13}}{7} ) are points on the unit circle.

3 0
3 years ago
Read 2 more answers
What is the equation of a line that goes through the point (0,-3/5) and has a slope of -1
svp [43]

Answer: y  =  − x − 3 /5

Step-by-step explanation:

Use the formula  

y = m x + b  in order to solve for  b . Then, plug in known values.

y  =  − x − 3 /5

7 0
3 years ago
Other questions:
  • Need help, I don’t understand
    5·1 answer
  • The volume of a rectangular prism is 156 cubic centimeters. The base of the prism has an area of 12 square centimeters.
    8·1 answer
  • What is 3/18 written in simplest form explain how you found you answer
    6·2 answers
  • If g( n ) = 3 n - 2, then what is the value of g(10)?<br><br> 4<br> 28<br> 308<br> 24
    5·1 answer
  • Solve for t.<br> 3(t – 13) = 18
    9·2 answers
  • Hello twngan sus puntos!!​
    12·2 answers
  • Was a major accomplishment of both Tutankhamun and Rameses II.<br><br><br><br><br> Plz help
    9·1 answer
  • Is the data symmetrical? If not, which way is the data skewed?
    9·2 answers
  • For 6 consecutive days, Alejandro studied for 5 minutes more each day than he did the previous day. Which best represents the ch
    5·2 answers
  • Instructions: Find the missing side. Round your answer to the nearest tenth.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!