Hello! I can help!
10:
a. 4-5 magazines interval contains the fewest data values.
b. There are 20 students in the class. 15 + 3 + 2 is 20.
c. Ignore the 6-7 interval and count the students from the others. 17/20 students read less than 6 magazines. 85% of students read less than 6 magazines.
d. You can’t exactly find the mean of the data, because you don’t know the exact number of how many each student read. The median would be in the range of 2-3, but you can’t find that either. You can’t find any of them without the exact numbers.
11. There were way more than 12% of songs that took 5-8 seconds to download. The error was getting the number of songs that took that long to download and putting it as a percentage. 12/36 songs took 5-8 seconds to download. 12/36 equals 1/3 (0.333) or simply 33%. The real answer is that 33% of the songs took 5-8 seconds to download.
The height of the ladder on the building is 19.77 feet
<h3>How high does the ladder reach on the building?</h3>
Represent the height of the ladder on the building with h
So, the given parameters are:
Angle, x = 64 degrees
Length of ladder, l = 22 feet
The height of the ladder on the building is calculated using
sin(x) = h/l
Substitute the known values in the above equation
sin(64) = h/22
Multiply both sides by 22
h = 22 * sin(64)
Evaluate the product
h = 19.77
Hence, the height of the ladder on the building is 19.77 feet
Read more about elevation angles at
brainly.com/question/19594654
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16 because 48/3 = 16 and we know that he started with 50 chocolates then distributed 3 times the number of friends present. This is written as 50 - 3x. We also know that there were 2 chocolates left so -3x = 2 - 50 which when simplified is x = 48/3 which equals 16.
Answer:
Yes, the art supplies cost $29.73, and I believe she has what looks on the picture to be $57
Step-by-step explanation:
First setting up the first step of the equation
3/8*16=?
Does 16/1=16? Yes it does! So you can put 16/1 in place of the 16!
So, 3/8*16/1= 48/8
And 48/8=6
<span>The solution is 6! Do you have further questions?</span>
