1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Flauer [41]
3 years ago
6

Write an equation in point-slope form of the line through point J(-8,10) with slope -5.

Mathematics
1 answer:
mafiozo [28]3 years ago
5 0
Point-slope form is y - y1 = m(x - x1). If you apply that point and the slope to the formula (hence the name point-slope), you'd get y - 10 = -5(x + 8).

Hope this helps! :)

REVISE: I accidently put y instead of x in the -5(x + 8) part. It's fixed now.
You might be interested in
33. Suppose you were on a planet where the
tatyana61 [14]

<u>Answer:</u>

a) 3.675 m  

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth =9.8ms^-2

And on planet given = 2.0ms^-2

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula  </u>

\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}

Where H = max jump height,  

v0 = velocity of jump,  

Ø = angle of jump and  

g = acceleration due to gravity

Considering velocity and angle in both cases  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)  

g1 = 2.0ms^-2 and  

g2 = 9.8ms^-2

Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by  </u>

 \mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}

which is due to projectile motion of ball  

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,  

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0ms^-2  and g2 = 9.8ms^-2

We get h1 = 3.67m which is the required height

6 0
3 years ago
Raina's penny bank is  1/4  full. After she adds  360  pennies, it is  5/8  full. How many pennies can Raina's bank hold? ​
Triss [41]

Answer:

960

Step-by-step explanation:

We start with the variable "x". Let's call "x" Raina's penny bank.

After adding 360 pennies, at the end, she has 5/8x, or 5/8.

So we start with

(1/4)x + 360 = 5/8x

Let's subtract 1/4x from both sides

360 = 5/8x - 1/4x

Remember, we need to use common denominators to subtract, so 1/4 becomes 2/8

360 = 5/8x - 2/8x

Now we simplify to get

360=3/8x

Multiply the reciprocal of 3/8 to both sides which is 8/3

360 * 8/3 = x

Answer is 960 pennies.

Therefore Raina's bank hold 960 pennies.

4 0
2 years ago
Read 2 more answers
F(x)=x+1, g(x)=-x, and h(x)=x^2+1<br> find (g of)(x)
Dvinal [7]

Answer:

b

Step-by-step explanation:

6 0
3 years ago
What is the solution to <br> 4/a+5/3a&lt;3
scoray [572]
\dfrac{4}{a}+\dfrac{5}{3a} < 3\ \ \ |-3\ \ \ assume\ a\neq0\\\\\dfrac{3\cdot4}{3a}+\dfrac{5}{3a}-\dfrac{3a\cdot3}{3a} < 0\\\\\dfrac{12+5-9a}{3a} < 0\\\\\dfrac{-9a+17}{3a} < 0\iff 3a(-9a+17) < 0\\\\3a=0\to a=0\\\\-9a+17=0\to a=\dfrac{17}{9}
Look at the picture.
Answer:\ a\in\left(0;\ \dfrac{17}{9}\right)

3 0
3 years ago
A customer desires to mix her own concrete. The clerk knows that the ratio of cement to sand to gravel is 1:3:4. If the customer
Aleks [24]

Answer:

The quantity of cement use is 125 pounds

The quantity of sand use is 375 pounds

The quantity of gravel use is 500 pounds

Step-by-step explanation:

Given as :

The ratio of cement to sand to gravel = 1 : 3 : 4

The total quantity of dry mix required = 1000 pounds

Let The quantity of cement required = 1 × x pounds

The quantity of sand required = 3 × x pounds

The quantity of gravel required = 4 × x pounds

So, According to question

The total quantity of dry mix required = The quantity of cement required + The quantity of sand required + The quantity of gravel required

Or, x + 3 x + 4 x = 1000 pounds

Or, 8 x = 1000 pounds

∴  x = \frac{1000}{8}

I.e x = 125

So , The quantity of cement required = 1 × 125 pounds = 125 pounds

The quantity of sand required = 3 × 125 pounds = 375 pounds

The quantity of gravel required = 4 × 125 pounds = 500 pounds

Hence The quantity of cement use is 125 pounds

The quantity of sand use is 375 pounds

The quantity of gravel use is 500 pounds

Answer

8 0
3 years ago
Other questions:
  • Zoe is a chemistry teacher earning a salary of $38,000 per year. She also tutors part-time, charging $20 per session. Which of t
    9·2 answers
  • Cody bought two burgers and two
    5·1 answer
  • How many feet are in 108 inches?
    5·2 answers
  • Tell whether the system has one solution, infinitely many solutions, or no solution.
    13·1 answer
  • What is the value of the expression 86.24-79764
    8·2 answers
  • The volunteers at a high school football team's concession stand are trying to decide on the price of the hot dogs they are sell
    12·1 answer
  • I need help with this assignment
    12·1 answer
  • Pleasee helppp
    6·1 answer
  • Is my answer right? if not break the hard news and give me the right one​
    7·1 answer
  • If you do these 2 problems you get 100 points
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!