Answer:
A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle? Here the number of animals and the number of days are in inverse proportion. Hence the food will last 4 days.
Using the law of sines:
Solve for b:
Answer:
7.708
We have the data set:
{79, 83, 82, 78, 79, 77, 80, 73, 82, 72}
This data set has 10 items.
To complete the data summary is helpful to sort the data:
{72, 73, 77, 78, 79, 79, 80, 82, 82, 83}
The minimum value is 72.
<em>The quartile divides the data set in 4 parts. </em>
<em>The first quartile is the value for which 25% of the data is below.</em>
<em>The second quartile is the value for which 50% of the data is below. The second quartile is equivalent to the median.</em>
<em>The third quartile is the value for which 75% of the data is below.</em>
In this data set, as its size is a even number, the quartile fall between two positions, so we will calculate the average of this numbers.
The first quartile will fall in the position 0.25*10=2.5. Then we can calculate the 1st quartile as the average between the 2nd and 3rd number of the data set.
This values are 73 (2nd position) and 77 (3rd position), so the average is:
We can repeat this with the other quartiles:
Then:
The first quartile is 75.
The median (second quartile) is 79.
The third quartile is 82.
The maximum value is 83.