Answer:
Weights of at least 340.1 are in the highest 20%.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
a. Highest 20 percent
At least X
100-20 = 80
So X is the 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.842.
Weights of at least 340.1 are in the highest 20%.
Multiply then simplify, that's doing the same work twice...anyway
x^3+x^2y+xy^2-x^2y-xy^2-y^3
x^3-y^3 which if factored is:
(x-y)(x^2+xy+y^2) which is what you started with :)
Answer:
Approximately 67.348 litres can be put in six hemispherical bowl with a diameter of 35 centimetres.
Step-by-step explanation:
The volume of a hemisphere (
), measured in cubic centimetres, is obtained from this formula:
Where 
is the radius of the hemisphere, measured in centimetres.
We know that radius is the half of the diameter (
), measured in centimetres, then:
(
)
Now, we get the volume of each hemispherical bowl:
The total volume of six hemispherical bowl is:
From Physics we know that 1 litre equals 1000 cubic centimetres. Then:
Approximately 67.348 litres can be put in six hemispherical bowl with a diameter of 35 centimetres.
Answer:
The non-equivalent ratio is 4:5.
Step-by-step explanation:
2/3 4/6 and 8/12 are equivalent because they are all multiples of each other.
