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frez [133]
3 years ago
8

What is this property 3+(2+7)= 3+(7+2)

Mathematics
1 answer:
RSB [31]3 years ago
5 0

Answer: Associative prop

Step-by-step explanation:

Associative Property of Addition (Numbers) 5 + (6 + 7) = (5 + 6) + 7

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Point oh oh zero eight
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What is the negation of the following statement: "n is divisible by 6 or n is divisible by both 2 and 3."
olganol [36]

Answer:

H.''n is not divisible by 6 and n is not divisible by both 2 and 3.

Step-by-step explanation:

We are given that  a statement ''n is divisible by 6 or n is divisible by both 2 and 3.''

We have to write the negation of the  given statement.

Negation: If  a statement p is true then its negations is  p is false.

n is divisible by 6 then negation is n is not divisible by 6.

n is divided by both 2 and 3 then negation is n is not divisible  by both 2 and 3.

Therefore, negation of given statement

''n is not divisible by 6 and n is not divisible by both 2 and 3.

Hence, option H is true.

3 0
3 years ago
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-v + 5 + 6v = 1 + 5v + 3
Dima020 [189]

Answer:

v does not exist

Step-by-step explanation:

5v+5=4+5v

there is no v

5 0
3 years ago
A large pool of adults earning their first driver’s license includes 50% low-risk drivers, 30% moderate-risk drivers, and 20% hi
Mamont248 [21]

Answer:

The probability that these four will contain at least two more high-risk drivers than low-risk drivers is 0.0488.

Step-by-step explanation:

Denote the different kinds of drivers as follows:

L = low-risk drivers

M = moderate-risk drivers

H = high-risk drivers

The information provided is:

P (L) = 0.50

P (M) = 0.30

P (H) = 0.20

Now, it given that the insurance company writes four new policies for adults earning their first driver’s license.

The combination of 4 new drivers that satisfy the condition that there are at least two more high-risk drivers than low-risk drivers is:

S = {HHHH, HHHL, HHHM, HHMM}

Compute the probability of the combination {HHHH} as follows:

P (HHHH) = [P (H)]⁴

                = [0.20]⁴

                = 0.0016

Compute the probability of the combination {HHHL} as follows:

P (HHHL) = {4\choose 1} × [P (H)]³ × P (L)

               = 4 × (0.20)³ × 0.50

               = 0.016

Compute the probability of the combination {HHHM} as follows:

P (HHHL) = {4\choose 1} × [P (H)]³ × P (M)

               = 4 × (0.20)³ × 0.30

               = 0.0096

Compute the probability of the combination {HHMM} as follows:

P (HHMM) = {4\choose 2} × [P (H)]² × [P (M)]²

                 = 6 × (0.20)² × (0.30)²

                 = 0.0216

Then the probability that these four will contain at least two more high-risk drivers than low-risk drivers is:

P (at least two more H than L) = P (HHHH) + P (HHHL) + P (HHHM)

                                                            + P (HHMM)

                                                  = 0.0016 + 0.016 + 0.0096 + 0.0216

                                                  = 0.0488

Thus, the probability that these four will contain at least two more high-risk drivers than low-risk drivers is 0.0488.

6 0
3 years ago
Help plz answer what is 4.6-2.46
kykrilka [37]

Answer:

2.14

Step-by-step explanation:

Basically its like regular subtraction

4.6

-

2.46

________

2.14

4 0
3 years ago
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