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3 years ago

7

Help needed asap!!,.........

1 answer:

Kaylis [27]3 years ago

3 0

Answer:

C: Reflection across the y-axis and a translation right two units.

Step-by-step explanation:

FLVS Geometry, eh? I did that class last year.

Anyway, when you apply a reflection across the y-axis, the original shape will flip to the upper-right quadrant because it got reversed in its x coordinates (x, y becomes -x, y). From there, all you have to do is translate two to the right.

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16.089 round to nearest 10

zepelin [54]

20 because 16 is greater than 15 and we round the number up.

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3 years ago

Lcm of 2/5 and 5/18?

SSSSS [86.1K]

Answer:

10

Step-by-step explanation:

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3 years ago

Simplify the trigonometric expression sin(4x)+2 sin(2x) using Double-Angle

drek231 [11]

Answer:

${ \bf{ = \sin(4x) + 2 \sin(2x) }} \\ = { \bf{2 \sin(2x) \cos(2x) + 4 \sin(x) \cos(x) }} \\ { \bf{ = 4 \sin(x) \cos(x) . ({ \cos }^{2} x - { \sin}^{2} }x) + 4 \sin(x) \cos(x) } \\ = { \bf{4 \sin(x) \cos(x) ( { \cos }^{2}x - { \sin }^{2}x + 1) }} \\ = { \bf{4 \sin(x) \cos(x) }(2 { \cos }^{2} x)} \\ = { \bf{8 \sin(x) { \cos}^{3}x }}$

8 0

3 years ago

The numbers of teams remaining in each round of a single-elimination tennis tournament represent a geometric sequence where an i

Anit [1.1K]

Answer:

$a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}$

Step-by-step explanation:

We are given the following in the question:

The numbers of teams remaining in each round follows a geometric sequence.

Let a be the first the of the geometric sequence and r be the common ration.

The $n^{th}$ term of geometric sequence is given by:

$a_n = ar^{n-1}$

$a_4 = 16 = ar^3\\a_6 = 4 = ar^5$

Dividing the two equations, we get,

$\dfrac{16}{4} = \dfrac{ar^3}{ar^5}\\\\4}=\dfrac{1}{r^2}\\\\\Rightarrow r^2 = \dfrac{1}{4}\\\Rightarrow r = \dfrac{1}{2}$

the first term can be calculated as:

$16=a(\dfrac{1}{2})^3\\\\a = 16\times 6\\a = 128$

Thus, the required geometric sequence is

$a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}$

4 0

3 years ago

ABCD is a rectangle ,its diagonals meet at O.If AO = 5x+1 and BO = 4x+9,find the length of the diagonals .(lengths in cm).

Sergeu [11.5K]

Answer:

82 cm

Step-by-step explanation:

In rectangles diagonals are equal and bisect each other

AO = BO

5x + 1 = 4x + 9

Subtract 1 from both sides

5x = 4x + 9 -1

5x = 4x + 8

Subtract 4x from both the sides

5x - 4x = 8

x = 8

AO = 5x + 1

= 5*8 +1

= 40 + 1

AO= 41 cm

Diagonal = 2*41 = 82 cm

7 0

3 years ago