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harkovskaia [24]
4 years ago
15

could you answer both these questions? Will give brainilest!! To answer give eithr a,b,c or d. THANK U

Mathematics
2 answers:
fgiga [73]4 years ago
8 0

Answer:

1st qns: A

2nd qns: B

Step-by-step explanation:

The ans is A as its 1/6

Alchen [17]4 years ago
8 0

Answer:1.  A      2.B

1.  Sample space- 1,2,3,4,5,6

favarable outcome- 3

1/6

2. Sample space- 1,2,3,4,5,6

favorable outcome- 4,5

2/6

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Answer these 3 pleaseeeeeeeeeeeeeeeeeeeeeeeeee
irakobra [83]

Answer:

a answer is given below

3(18-7)+2

3×11+2

33+2

35

b answer is given:

7a-3b

7×4-3×3

28-9

19

c answer is given:

4/5x+7.2

60/5

22+7.2

19.2

8 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIEST IF RIGHT
RUDIKE [14]

Answer:

<u>Distance formula between points (x₁, y₁) and (x₂,y₂) is:</u>

  • d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2

<u>Substitute (x₁, y₁) with (6, 5),  (x₂,y₂) with (x, y) and d with 5:</u>

  • 5 = \sqrt{(x-6)^2+(y-5)^2

Correct choice is A

7 0
3 years ago
∆ ABC is similar to ∆DEF and their areas are respectively 64cm² and 121cm². If EF = 15.4cm then find BC.​
lyudmila [28]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

★ ∆ ABC is similar to ∆DEF

★ Area of triangle ABC = 64cm²

★ Area of triangle DEF = 121cm²

★ Side EF = 15.4 cm

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

★ Side BC

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

Since, ∆ ABC is similar to ∆DEF

[ Whenever two traingles are similar, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. ]

\therefore \tt \boxed{  \tt \dfrac{area( \triangle \: ABC )}{area( \triangle \: DEF)} =  { \bigg(\frac{BC}{EF} \bigg)}^{2}   }

❍ <u>Putting the</u><u> values</u>, [Given by the question]

• Area of triangle ABC = 64cm²

• Area of triangle DEF = 121cm²

• Side EF = 15.4 cm

\implies  \tt  \dfrac{64   \: {cm}^{2} }{12 \:  {cm}^{2} }  =  { \bigg( \dfrac{BC}{15.4 \: cm} \bigg) }^{2}

❍ <u>By solving we get,</u>

\implies  \tt    \sqrt{\dfrac{{64 \: cm}^{2} }{ 121 \: {cm}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \sqrt{\dfrac{{(8 \: cm)}^{2} }{  {(11 \: cm)}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \dfrac{8 \: cm}{11 \: cm}    =   \dfrac{BC}{15.4 \: cm}

\implies  \tt    \dfrac{8  \: cm \times 15.4 \: cm}{11 \: cm}    =   BC

\implies  \tt    \dfrac{123.2 }{11 } cm   =   BC

\implies  \tt   \purple{  11.2 \:  cm}   =   BC

<u>Hence, BC = 11.2 cm.</u>

{\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}

★ Figure in attachment.

\rule{280pt}{2pt}

4 0
2 years ago
Helpppp this very confusing
alukav5142 [94]
What is it
I don't get it done
3 0
3 years ago
I need help please, also if you could put the steps in and check that would be great. Also whoever does gets brainliest
denis23 [38]

Answer:  #7 is A and #8 is D

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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