Answer:
At a combined speed of 6 in/min, it takes us 24 mins to clean the wall
Step-by-step explanation:
Since the question did not provide the speed with which each student cleans, we can make assumptions. This is so that we can solve the question before us
Assuming student 1 cleans at a speed of 2 inches per minute, student 2 cleans at a speed of 2½ inches per minute & student 3 cleans at a speed of 1½ inches per minute.
Let's list the parameters we have:
Height of wall (h) = 12 ft, Speed (student 1) = 2 in/min, Speed (student 2) = 2½ in/min, Speed (student 3) = 1½ in/min
Speed of cleaning wall = Height of wall ÷ Time to clean wall
Time to clean wall (t) = Height of wall ÷ Speed of cleaning wall
since students 1, 2 and 3 are working together, we will add their speed together; v = (2 + 2½ + 1½) = 6 in/min
1 ft = 12 in
Time (t) = h ÷ v = (12 * 12) ÷ 6 = 144 ÷ 6
Time (t) = 24 mins
Answer: Thus when transforming from ABC to A'B'C', the lengths are scaled by a factor of 0.5 .
Step-by-step explanation:
Since the triangles are similar, the ratio of their sides are equal.
And we can count the number of blocks over which AC and A'C' is drawn and take them to be their length,
Therefore,
AC = 16
A'C'= 8
Thus when transforming from ABC to A'B'C', the lengths are scaled by a factor of 0.5 .
Measuring the tans of the angles by taking the ratio of opposite by adjacent, we get,
tanA =
tanA'=
which means tanA= tanA'
The angles do not change.
Thus when transforming from ABC to A'B'C', the lengths are scaled by a factor of 0.5 .
Answer:
First equation is -425
Second equation is 11.25
Step-by-step explanation:
First equation we can write as
computing
When i=0 ->
When i=1 ->
...
When i=7 ->
then replacing each term we have
For the second equation we'll have 9 terms, solving in a similar fashion
When i=1 ->
When i=2 ->
When i=3 ->
...
When i=9 ->
So we have 0.25 + 0.50 + 0.75 + 1.00 + 1.25 + 1.50+ 1.75 +2.00 +2.25